02-20-2014
Call a UNIX script inside another and dont wait for it
Hi
I have two scripts script1.sh and script2.sh(say this script is a long running).
I want to call script2.sh inside and script1.sh,but when i call script2.sh i dont want to wait for script2 to complete and want this to run in back ground and go on next commands in script 1.sh and finally at the end want to check for script2 process ? I need the
- syntax to call script2 in script which doesnt wait and runs in back ground
- check for script 2 is complete at end of script 1
Would appreciate if someone can give a psuedo code for this
Thanks in advance
Matt
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LEARN ABOUT LINUX
service
service(8) System Manager's Manual service(8)
NAME
service - run a System V init script
SYNOPSIS
service SCRIPT COMMAND [OPTIONS]
service --status-all
service --help | -h | --version
DESCRIPTION
service runs a System V init script in as predictable environment as possible, removing most environment variables and with current working
directory set to /.
The SCRIPT parameter specifies a System V init script, located in /etc/init.d/SCRIPT. The supported values of COMMAND depend on the
invoked script, service passes COMMAND and OPTIONS it to the init script unmodified. All scripts should support at least the start and
stop commands. As a special case, if COMMAND is --full-restart, the script is run twice, first with the stop command, then with the start
command.
service --status-all runs all init scripts, in alphabetical order, with the status command.
EXIT CODES
service calls the init script and returns the status returned by it.
FILES
/etc/init.d
The directory containing System V init scripts.
ENVIRONMENT
LANG, TERM
The only environment variables passed to the init scripts.
SEE ALSO
/etc/init.d/skeleton,
update-rc.d(8),
init(8),
invoke-rc.d(8).
Jan 2006 service(8)