ksh : Building an array based on condition result Post: 302888974

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Top Forums Shell Programming and Scripting ksh : Building an array based on condition result Post 302888974 by popeye on Tuesday 18th of February 2014 08:05:15 AM

02-18-2014

Registered User

ksh : Building an array based on condition result

I want to build an Errorlog. I would like to build an array as I move through the if statements and print the array once all error conditions have been defined. The results need to be comma delimited.

tsver will be static "1.9.6(2)"
other vars $prit $lt $rt can have the same or a different value as tsver.
For those vars not matching tsver, their values should be written to a csv.

Example errorlog file

Quote:

name,ip,pri,left,right,
cow,10.9.1.135,,,,
sheep,10.9.1.139,,,,
hen,10.9.1.141,1.3.6(2),,,
rooster,10.9.1.158,,,,
duck,10.9.1.162,,1.1.1(2),,
pig,10.9.1.164,,1.9.5(2),,
horse,10.9.1.171,,,2.2.2(2),

This code works, but it seems cheep .... My question is how do I build an array in ksh as I step through the version mismatch tests ?

Code:

 if [[ "$prit" != "$tsver" ]]
   then 
   echo -n "$prit," >> Errorlog
   else 
   echo -n "," >> Errorlog
  fi
#
if [[ "$lt" != "$tsver" ]]
   then
   echo -n "$lt," >> Errorlog
   else
   echo -n "," >> Errorlog
  fi

#
if [[ "$rt" != "$tsver" ]]
   then
   echo -n "$rt," >> Errorlog
   else
   echo -n "," >> Errorlog
  fi

Looking through Unix shell by Quigley and searching the web. But havent found anything that gives a good example.

THANKS !!

popeye

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GO-BUILD(1)						      General Commands Manual						       GO-BUILD(1)

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DESCRIPTION

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OPTIONS

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SEE ALSO

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