awk to grep ".do" Post: 302888394

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Top Forums Shell Programming and Scripting awk to grep ".do" Post 302888394 by Don Cragun on Friday 14th of February 2014 05:08:13 AM

02-14-2014

Registered User

If I understand correctly what the OP was trying to do, the simple fix would be to change:

Code:

awk -F\" '($2 ~ ".do\"){print $2}' filename.log | awk '{print $2}' | sort | uniq -c | sort -r

to:

Code:

awk -F\" '($2 ~ /\.do/){print $2}' filename.log | awk '{print $2}' | sort | uniq -c | sort -r

A slightly more complex awk script would eliminate the need for the 2nd invocation of awk, the 1st invocation of sort, and the invocation of uniq:

Code:

awk -F\" '
$2 ~ /[.]do/ {
        split($2, f2f, /[ \t]+/)
        c[f2f[2]]++
}
END {   for(i in c) printf("%4d %s\n", c[i], i)
}' filename.log | sort -r

and still produce the same output.

Don Cragun

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