I have a date that looks like this:
2008/100:18:40:47.040
I need it to look like this:
2008 04 09 18 40 47 040
I have looked at datecalc and it doesn't seem like it takes the day of year for this year (or whatever year is input) and converts it into month and day. It also has to account... (2 Replies)
Hi,
I'm working on a Informix4gl module. I'm just trying to find out any built-in function to fetch only the year/month from an INTERVAL YEAR TO MONTH data value.
Please let me know, if there are any functions to do this. If not, let me know for any alternative solutions to attain this.
... (5 Replies)
Hi
I have files like
abc_cd_20110302_123423
abc_cd_ef_20110301_123423
abc_cd_ef_20110403_123423
abc_ef_20110401_123423
I want to extract the
the year and month associated with each file.
I tried
logfileyearmonth=`echo $logfile | awk -F_'{print $NF}'`
Any other way can I... (6 Replies)
Discussion started by: dgmm
6 Replies
6. Forum Support Area for Unregistered Users & Account Problems
So why does the password reset page tell me I've answered the question incorrectly?
First, I tried to register. Never received an email. So I tried to register with a different email/username. I was told it was taken. I tried to have a password sent to my email, but June is not the 6th month... (1 Reply)
Hi All,
I find all files for same month and year
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 21 2012 d.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 2012 f.txt
-rwxr-xr-x 1... (8 Replies)
Hi All,
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 a.txt
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 b.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 2012 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 24 2012 d.txt... (16 Replies)
The following bash command line works for the last day of the month. Test by replacing the 1 with tomorrows day of month number
&& echo "Day before tomorrow"Can it be used within crontab? As
* * 28-31 * * && echo "Today ls last day of month" >>/tmp/crontabtestI tried to test crontab with... (1 Reply)
Discussion started by: lsatenstein
1 Replies
LEARN ABOUT SUNOS
cal
cal(1) User Commands cal(1)NAME
cal - display a calendar
SYNOPSIS
cal [ [month] year]
DESCRIPTION
The cal utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If
no operands are specified, a calendar for the current month is written.
OPERANDS
The following operands are supported:
month Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the current
month.
year Specify the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current
year.
ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE, LC_TIME,
LC_MESSAGES, and NLSPATH.
TZ Determine the timezone used to calculate the value of the current month.
EXIT STATUS
The following exit values are returned:
0 Successful completion.
>0 An error occurred.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWesu |
+-----------------------------+-----------------------------+
|Interface Stability |Standard |
+-----------------------------+-----------------------------+
SEE ALSO calendar(1), attributes(5), environ(5), standards(5)NOTES
An unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To
see this calendar, type:
cal 9 1752
The command cal 83 refers to the year 83, not 1983.
The year is always considered to start in January.
SunOS 5.10 1 Feb 1995 cal(1)