Dear Masters,
Here i have some doubts can anyone clarify?.
Is it possible to grep the lines by specifying the line numbers.
I know the line number which i want to grep.
example:
grep 40th line filename
grep 50th line filename
Need ur comments. (4 Replies)
Hi all,
I want to display line number for matching string in a file. can anyone please help me.
I used
grep -n "ABC" file
so it displays
6 ABC.
But i only want to have line number,i don't want that it should prefix matching context with line number.
Actually my original... (10 Replies)
Hello,
I looking to use grep to return a string with exactly n matches.
I'm building off this:
ls -aLl /bin | grep '^.\{9\}x' | tr -s ' '
-rwxr-xr-x 1 root root 632816 Nov 25 2008 vi
-rwxr-xr-x 1 root root 632816 Nov 25 2008 view
-rwxr-xr-x 1 root root 16008 May 25 2008... (7 Replies)
I have a txt file as database. when i run my program what it does is it ask me for 3 name and stored in the file as
name1:name2:name3:1
when u enter 3 name it add those in file as above format and add 1 at the end. I what i want is if i enter same names again it changes that 1 to 2 and so... (3 Replies)
Hello,
Thanks in advance for the query.
There is a log file abcd.log which has multible line like this.
"hello1" , "hello2", "hello3" , "hello4" , "hello5"
I want to grep for the lines which has "hello4" & "hello5" and use "hello2" to grep the same log file again.
All these should... (8 Replies)
I am attempting to grep an exact string from a series of files within a directory and append that output to the filename when it is present in the file. I've been after this all day with no luck. Thanks for your help in advance :wall:. (4 Replies)
Hi,
I have a list of zipped files. I want to grep for a string in all files and get a list of file names that contain the string. But without unzipping them before that, more like using something like gzcat.
My OS is:
SunOS test 5.10 Generic_142900-13 sun4u sparc SUNW,SPARC-Enterprise (8 Replies)
Hello,
I am newbie to bash scripting. Could someone help me with the following.
I have log file with output as shown below
**************************LOG*************************
11/20/2013 9:11:23.64 Pinging xx.xx.xx.xx with 32 bytes of data:
11/20/2013 9:11:23.64 Reply from xx.xx.xx.xx:... (4 Replies)
I have below code inside my awk script
if ( $0 ~ /SVC IN:/ )
{
svc_in=substr( $0,23 , 3);
if (msg_start == 1 && msg_end == 0)
{
msg_arr=$0;
}
}
else if ( $0 ~ /^SVC OUT:/ )
{
svc_out=substr( $0, 9, 3);
if (msg_start == 1 && msg_end == 0)
... (6 Replies)
Discussion started by: bhagya123
6 Replies
LEARN ABOUT DEBIAN
racc
racc(1) General Commands Manual racc(1)NAME
racc - Ruby LALR parser generator
SYNOPSIS
racc [options] file
DESCRIPTION
Racc is a LALR(1) parser generator. It is written in Ruby itself, and generates Ruby program.
OPTIONS -g, --debug
output parser for user level debugging.
-o, --output-file <outfile>
file name of output. [<fname>.tab.rb]
-e, --executable <rubypath>
insert #! line in output. ('ruby' to default)
-E, --embedded
output file which don't need runtime.
-l, --no-line-convert
never convert line numbers. (for ruby<=1.4.3)
-c, --line-convert-all
convert line numbers also header and footer.
-a, --no-omit-actions
never omit actions.
-v, --verbose
create <filename>.output file.
-O, --log-file <fname>
file name of verbose output. [<fname>.output]
-C, --check-only
syntax check only.
-S, --output-status
output status time to time.
--no-extentions
run without any ruby extentions.
-h, --help
print this message and quit.
--version
print version and quit.
--runtime-version
print runtime version and quit.
--copyright
print copyright and quit.
SEE ALSO
/usr/share/doc/racc/html.en/index.html (English) or /usr/share/doc/racc/html.ja/index.html (Japanese).
April 2005 racc(1)