Dear Masters,
Here i have some doubts can anyone clarify?.
Is it possible to grep the lines by specifying the line numbers.
I know the line number which i want to grep.
example:
grep 40th line filename
grep 50th line filename
Need ur comments. (4 Replies)
Hi all,
I want to display line number for matching string in a file. can anyone please help me.
I used
grep -n "ABC" file
so it displays
6 ABC.
But i only want to have line number,i don't want that it should prefix matching context with line number.
Actually my original... (10 Replies)
Hello,
I looking to use grep to return a string with exactly n matches.
I'm building off this:
ls -aLl /bin | grep '^.\{9\}x' | tr -s ' '
-rwxr-xr-x 1 root root 632816 Nov 25 2008 vi
-rwxr-xr-x 1 root root 632816 Nov 25 2008 view
-rwxr-xr-x 1 root root 16008 May 25 2008... (7 Replies)
I have a txt file as database. when i run my program what it does is it ask me for 3 name and stored in the file as
name1:name2:name3:1
when u enter 3 name it add those in file as above format and add 1 at the end. I what i want is if i enter same names again it changes that 1 to 2 and so... (3 Replies)
Hello,
Thanks in advance for the query.
There is a log file abcd.log which has multible line like this.
"hello1" , "hello2", "hello3" , "hello4" , "hello5"
I want to grep for the lines which has "hello4" & "hello5" and use "hello2" to grep the same log file again.
All these should... (8 Replies)
I am attempting to grep an exact string from a series of files within a directory and append that output to the filename when it is present in the file. I've been after this all day with no luck. Thanks for your help in advance :wall:. (4 Replies)
Hi,
I have a list of zipped files. I want to grep for a string in all files and get a list of file names that contain the string. But without unzipping them before that, more like using something like gzcat.
My OS is:
SunOS test 5.10 Generic_142900-13 sun4u sparc SUNW,SPARC-Enterprise (8 Replies)
Hello,
I am newbie to bash scripting. Could someone help me with the following.
I have log file with output as shown below
**************************LOG*************************
11/20/2013 9:11:23.64 Pinging xx.xx.xx.xx with 32 bytes of data:
11/20/2013 9:11:23.64 Reply from xx.xx.xx.xx:... (4 Replies)
I have below code inside my awk script
if ( $0 ~ /SVC IN:/ )
{
svc_in=substr( $0,23 , 3);
if (msg_start == 1 && msg_end == 0)
{
msg_arr=$0;
}
}
else if ( $0 ~ /^SVC OUT:/ )
{
svc_out=substr( $0, 9, 3);
if (msg_start == 1 && msg_end == 0)
... (6 Replies)
Discussion started by: bhagya123
6 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)