Hi- I have issue with the code to get the input file reformat
--Goal is reformat and print out only column name one per line, leading space or trailing space will be removed...
--TABLE1.DDL as input file, and content of file as show below
--code to reformat and print out the column in SELECT statement only:
result does not look right as what I wanted
--expect output:
--test hung on COL5 and awk went into infinite loop. the COL3 also print on same line as COL2. that is wrong too.
what should I change to get the expect result? still try to learn awk should it look for comma to format a line? and we don't have gawk.
Last edited by Corona688; 01-21-2014 at 02:56 PM..
If I have data as below :
1,ABC,XXXX
2,ABC000,YYYY
3,DEF,AAAA
4,ABC0,ZZZZ
I want to get records whose 2nd col exactly match with word 'ABC'
I am using command below :
awk -F"," '$2~/ABC/' Filename
It is retrieving records as -
1,ABC,XXXX
2,ABC000,YYYY
4,ABC0,ZZZZ
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Records
P1
10,23423432
,77:1
,234:2
P2
10,9089004
,77:1
,234:2
,87:123
,9898:2
P3
456456
P1
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P2
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