I am trying to use a script to replace the header of each file, whose filename are stored within the array $test, using the sed command within a Perl script as follows:
$count = 0;
while ( $count < $#test )
{
`sed -e 's/BIOGRF 321/BIOGRF 332/g' ${test} > 0`;
`cat 0 >... (2 Replies)
Hi,
Is there any way I can grep an array against another array?
Basically here's what I need to do.
There will be an array containing some fixed texts and I have to check whether some files contain these lines. Reading the same files over and over again for each different pattern doesnt seem... (1 Reply)
Hi All,
I wanted to add 1 year to the system date in my script.
say export start_date=`date +%F`
echo $start_date
o/p of this is 2009-09-02
To this i want to add 1 year.
the output i need here is 2010-09-02
can anybody help me ?
Thanks in advance,
Vinay (4 Replies)
Hi Everyone,
#!/usr/bin/perl
use strict;
use warnings;
my @test=("a;b;qqq;c;d","a;b;ggg;c;d","a;b;qqq;c;d");
would like to split the @test array into two array:
@test1=(("a;b;qqq;c;d","a;b;qqq;c;d"); and @test2=("a;b;ggg;c;d");
means search for 3rd filed.
Thanks
find the... (0 Replies)
Hi everyone
I have one question about using array in perl. let say I have several log file in one folder.. example
test1.log
test2.log
test3.log
and the list goes on..
how to make an array for this file? It suppose to detect log file in the current directory and all the log file will... (3 Replies)
I have an array and two variables as below,
I need to check if $datevar is present in $filename.
If so, i need to replace $filename with the values in the array.
I need the output inside an ARRAY
How can this be done.
Any help will be appreciated. Thanks in advance. (2 Replies)
Hi all,
Not sure if this should be in the programming forum, but I believe it will get more response under the Shell Programming and Scripting FORUM.
Am trying to write a customized df script in Perl and need some help with regards to using arrays and file handlers.
At the moment am... (3 Replies)
okay so my job is requiring me to learn perl and i have never had any type of programming language... ever.
So i need to take a file that has data (nodes/points) with x, y, and z components.
Example of what the file contains is below:
RANDOM TEXT
RANDOM TEXT
Node # x pos ... (23 Replies)
Discussion started by: dets34
23 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)