Using echo to print arguments inside a function Post: 302881963

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I have a script that uses 2 arguments. I want to call the function part within this script using these same arguments. Below is what I came up with below script so far, any guidance would be helpful. Thank you! cat backup.sh #!/bin/bash function usage { echo "USAGE: $(basename $0)...

LEARN ABOUT SUNOS

print

print(1)							   User Commands							  print(1)

NAME

       print - shell built-in function to output characters to the screen or window

SYNOPSIS

   ksh
       print [ -Rnprsu [n]] [arg...]

DESCRIPTION

   ksh
       The shell output mechanism. With no flags or with flag - or -, the arguments are printed on standard output as described by echo(1).

OPTIONS

       The following options are supported:

       -n	       suppresses new-line from being added to the output.

       -R

       -r	       (raw  mode) ignore the escape conventions of echo. The -R option will print all subsequent arguments and options other than
		       -n.

       -p	       causes the arguments to be written onto the pipe of the process spawned with |& instead of standard output.

       -s	       causes the arguments to be written onto the history file instead of standard output.

       -u [ n ]        flag can be used to specify a one digit file descriptor unit number n on which the output will be placed. The default is 1.

EXIT STATUS

       The following exit values are returned:

       0	Successful operation.

       >0	Output file is not open for writing.

ATTRIBUTES

       See attributes(5) for descriptions of the following attributes:

       +-----------------------------+-----------------------------+
       |      ATTRIBUTE TYPE	     |	    ATTRIBUTE VALUE	   |
       +-----------------------------+-----------------------------+
       |Availability		     |SUNWcsu			   |
       +-----------------------------+-----------------------------+

SEE ALSO

       echo(1), ksh(1), attributes(5)

SunOS 5.10							    15 Apr 1994 							  print(1)

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