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Need to call a function with arguments

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# 1  
Old 12-17-2013
Need to call a function with arguments
I need to call a function within a code with $database and $ service as the arguments How do I proceed ? and how would a function be defined and these two arguments would be used inside the function?

Code:
calc_pref_avail $database $service



Best regards,
Vishal
# 2  
Old 12-17-2013
Hello Vishal,

Could you please be more specific in your requirement and let us know the input and expected output for same please.


Thanks,
R. Singh
# 3  
Old 12-17-2013
Hi Ravinder,

Below is the code in which there is a function call calc_pref_avail at last:

Code:
for service in `$ORACLE_HOME/bin/srvctl status service -d $database | awk '{print $2}'`
do
c="/product/10"
case $ORACLE_HOME in
  */product/10*)
Instance_pref=`$ORACLE_HOME/bin/srvctl config service -s $service -d $database | sed 's/\(.*: \)\(.*\)\( AVAIL:.*\)/\2/1;1q'`
Instance_avail=`$ORACLE_HOME/bin/srvctl config service -s $service -d $database | sed 's/\(.*AVAIL: \)\(.*\)/\2/g;1q'`;;
*)
calc_pref_avail;;


I need to pass $database and $ service as an argument to this function and suppose below is the way I define my function

Code:
calc_pref_avail   $database $service
{

-- code --
return inst_pref;

}

Please help me how to pass an argument to function call and while defining function how to return value and get that variable in the code from where function is called


Best regards,
Vishal
# 4  
Old 12-17-2013
Not knowing what shell you use, this is an excerpt from man bash:
Quote:
Shell Function Definitions
A shell function is an object that is called like a simple command and executes a compound command with a new set of positional
parameters. Shell functions are declared as follows:

name () compound-command [redirection]
function name [()] compound-command [redirection]
This defines a function named name. The reserved word function is optional. If the function reserved word is supplied, the
parentheses are optional. The body of the function is the compound command. ...
So define it like
Code:
calc_pref_avail ()
{
-- code  using $1 and $2  --
return inst_pref;  
}

and use it like
Code:
calc_pref_avail   $database $service

This User Gave Thanks to RudiC For This Post:
Vishal_dba
# 5  
Old 12-17-2013
Hello,

Here is the example for a function which will be called by arguments.

Code:
check_file()
{
for y in $*
do
if [[ -f $y ]]
then
rm $y
fi
done
}
### calling function as follows with arguments
check_file ${FILE1} ${FILE2}



Hope this may help.



Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Vishal_dba
# 6  
Old 12-17-2013
I need to get two values from this function as below:

Code:
    if [ "${line:0:21}" = 'Preferred instances: ' ]; then
      pref=($(echo "${line:21}"|sed 's/,/\n/g'));
    else
      avail=($(echo "${line:21}"|sed 's/,/\n/g'));
    fi


I need values of $pref and $avail from this function.Is there a way to combine these values and return as a 1 value since I understand that a function can return a single value .Thereafter after returning these values I can again get the 2 values in the code from where I called this function


Best regards,
Vishal
# 7  
Old 12-17-2013
echo the two values and assign to / read into caller's variables.
Code:
function A () { echo ABC CDE; }
A| { read C D; echo $D: $C; }
E=$(A)
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