Hi All,
My script is reading a log file line by line
log file is like ;
19:40:22 :INFO Total time taken to Service External Request---115ms
19:40:25 DEBUG : Batch processed libdaemon.x86_64 0-0.10-5.el5 - u
19:40:22 INFO Total time taken to Service External Request---20ms
19:40:24... (4 Replies)
Hey. This is pretty easy stuff but I'm learning the basics of Unix at the moment so keep that in mind. I have to:
1) Write a C-shell script to monitor user activity on the server for 13 minutes.
2) Then print the smallest and largest number of users during these 13 minutes.
I have this:
1)... (2 Replies)
Hey,
This is a long-shot however, I am stuck with the following problem:
I have the output from ls -la, and I want to sort some of that data out by using AWK to filter it.
ls -la | awk -f scriptname.awk
Input:
For example:
drwxr-xr-x 3 user users 4096 2010-03-14 20:15 bin/... (5 Replies)
Hii i have a file with data as shown below. Here i need to remove duplicates of the rows in such a way that
it just checks for 2,3,4,5 column for duplicates.When deleting duplicates,retain largest row i.e with many columns with values should be selected.Then it must remove duplicates such that by... (11 Replies)
Hi,
Here's my data -
aa
bb
cc
aa
dd
ee
Now I need to find the smallest block surrounded by aa & dd. Following is not helpful -
sed -n '/aa/,/dd/p' file
I need only -
aa
dd (1 Reply)
Input file :
5 20
500 2
20 41
41 0
23 1
Desired output :
5
2
20
0
1
By comparing column 1 and 2 in each line, I hope can print out the column with smallest number.
I did try the following code, but it don't look good :( (2 Replies)
Hi,
Anybody know how to print out the record that shown smallest number among column 3 and column 4
Case 1 Input :
37170 37196 77 51
37174 37195 73 52
37174 37194 73 53
Case 1 Output :
37170 37196 77 51
Case 2 Input :
469613 469660 73 ... (4 Replies)
Hi All
I need to find the smallest values between replicates id (column1)
Input file:
a name1 1200
a name2 800
b name1 100
b name2 150
b name3 4output:
a name2 800
b name3 4
Do you have any suggestion?
Thank you! (9 Replies)
Discussion started by: giuliangiuseppe
9 Replies
LEARN ABOUT REDHAT
dgeequ
DGEEQU(l) ) DGEEQU(l)
NAME
DGEEQU - compute row and column scalings intended to equilibrate an M-by-N matrix A and reduce its condition number
SYNOPSIS
SUBROUTINE DGEEQU( M, N, A, LDA, R, C, ROWCND, COLCND, AMAX, INFO )
INTEGER INFO, LDA, M, N
DOUBLE PRECISION AMAX, COLCND, ROWCND
DOUBLE PRECISION A( LDA, * ), C( * ), R( * )
PURPOSE
DGEEQU computes row and column scalings intended to equilibrate an M-by-N matrix A and reduce its condition number. R returns the row scale
factors and C the column scale factors, chosen to try to make the largest element in each row and column of the matrix B with elements
B(i,j)=R(i)*A(i,j)*C(j) have absolute value 1.
R(i) and C(j) are restricted to be between SMLNUM = smallest safe number and BIGNUM = largest safe number. Use of these scaling factors is
not guaranteed to reduce the condition number of A but works well in practice.
ARGUMENTS
M (input) INTEGER
The number of rows of the matrix A. M >= 0.
N (input) INTEGER
The number of columns of the matrix A. N >= 0.
A (input) DOUBLE PRECISION array, dimension (LDA,N)
The M-by-N matrix whose equilibration factors are to be computed.
LDA (input) INTEGER
The leading dimension of the array A. LDA >= max(1,M).
R (output) DOUBLE PRECISION array, dimension (M)
If INFO = 0 or INFO > M, R contains the row scale factors for A.
C (output) DOUBLE PRECISION array, dimension (N)
If INFO = 0, C contains the column scale factors for A.
ROWCND (output) DOUBLE PRECISION
If INFO = 0 or INFO > M, ROWCND contains the ratio of the smallest R(i) to the largest R(i). If ROWCND >= 0.1 and AMAX is neither
too large nor too small, it is not worth scaling by R.
COLCND (output) DOUBLE PRECISION
If INFO = 0, COLCND contains the ratio of the smallest C(i) to the largest C(i). If COLCND >= 0.1, it is not worth scaling by C.
AMAX (output) DOUBLE PRECISION
Absolute value of largest matrix element. If AMAX is very close to overflow or very close to underflow, the matrix should be
scaled.
INFO (output) INTEGER
= 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = i, and i is
<= M: the i-th row of A is exactly zero
> M: the (i-M)-th column of A is exactly zero
LAPACK version 3.0 15 June 2000 DGEEQU(l)