Here is my awk code in a shell script:
localRecDir=/somedirectory/
#
awk -v LRD="$localRecDir" '{out = sprintf ("%s0000000%s"),LRD,substr($3,4) ; print > out; close(out)}' *.log
Here is the contents of my *.log file I am trying to parse with my script:
000007 0110 07-0001583
000007 ... (2 Replies)
Hi all,
Please help me decide this problem. I have a converter application getting its parameters by specified format. Ie: -date2007-02-14
Also I have a files named yyyyMMdd.rar format. So how do I convert the file name to it.
Input:
20070214.rar
Output:
-date2007-02-14
I wrote the... (2 Replies)
Hi There!
I have the following block of text in my input file
and in order to parse it correctly, i need to have
i.e. If a line starts with a number, ignore it else replace it with the number from the previous line until the first ','
So, for example,
15,9:5/12345
,10:1
... (5 Replies)
First of all I am VERY new to this so bare with me and try and explain everything even if it seems simple.
Basically I want to read a line of text from a html file. See if the line of text has a certain string in it. copy an unknown number of characters (the last 4 characters wiil be ".jpg" the... (1 Reply)
Hi,
I have the string like this ". Start : 06:53:11 - MON JUL 05, 2010"
I need to print the part "06:53:11 - MON JUL 05, 2010"
How i can do this?
Thanks,
Lenova (2 Replies)
i have something like this...
echo "teCertificateId" | awk -F'Id' '{ print $1 }' | awk -F'te' '{ print $2 }'
Certifica
the awk should remove 'te' only if it is present at the start of the string.. anywhere else it should ignore it.
expected output is
Certificate (7 Replies)
Hi ,
I have a simple text file with contents as below:
12345678900 971,76 4234560890
22345678900 5971,72 5234560990
32345678900 71,12 6234560190
the new csv-file should be like:
Column1;Column2;Column3;Column4;Column5
123456;78900;971,76;423456;0890... (9 Replies)
Hi ,
I am getting a string like
aaa,bbb,sdsdad,sdfsdf,sdfsdfdsf,rtyrtyr,45654654,ddfdfdfgdfg,dfgdfgdg...........
Now what I need is to format it.
So after each nth comma I need one newline. So the above will look like
when n=3
aaa,bbb,sdsdad,
sdfsdf,sdfsdfdsf,rtyrtyr,... (4 Replies)
I'm making a little game in Perl, and I am trying to remove the first instance of a character in an arbitrary string. For example, if the string is
"cupcakes"and the user enters another string that contains letters from "cupcake" e.g:
"sake"the original string will now look like this (below)... (3 Replies)
Discussion started by: whyte_rhyno
3 Replies
LEARN ABOUT DEBIAN
fmtcheck
FMTCHECK(3) BSD Library Functions Manual FMTCHECK(3)NAME
fmtcheck -- sanitizes user-supplied printf(3)-style format string
LIBRARY
Utility functions from BSD systems (libbsd, -lbsd)
SYNOPSIS
#include <bsd/stdio.h>
const char *
fmtcheck(const char *fmt_suspect, const char *fmt_default);
DESCRIPTION
The fmtcheck() scans fmt_suspect and fmt_default to determine if fmt_suspect will consume the same argument types as fmt_default and to
ensure that fmt_suspect is a valid format string.
The printf(3) family of functions cannot verify the types of arguments that they are passed at run-time. In some cases, like catgets(3), it
is useful or necessary to use a user-supplied format string with no guarantee that the format string matches the specified arguments.
The fmtcheck() was designed to be used in these cases, as in:
printf(fmtcheck(user_format, standard_format), arg1, arg2);
In the check, field widths, fillers, precisions, etc. are ignored (unless the field width or precision is an asterisk '*' instead of a digit
string). Also, any text other than the format specifiers is completely ignored.
RETURN VALUES
If fmt_suspect is a valid format and consumes the same argument types as fmt_default, then the fmtcheck() will return fmt_suspect. Other-
wise, it will return fmt_default.
SECURITY CONSIDERATIONS
Note that the formats may be quite different as long as they accept the same arguments. For example, "%p %o %30s %#llx %-10.*e %n" is com-
patible with "This number %lu %d%% and string %s has %qd numbers and %.*g floats (%n)". However, "%o" is not equivalent to "%lx" because the
first requires an integer and the second requires a long.
SEE ALSO printf(3)BUGS
The fmtcheck() function does not understand all of the conversions that printf(3) does.
BSD October 16, 2002 BSD