This might not be pretty, but you could do it in three steps:
That will replace first occurrences of "table_name". I don't want to touch the second column (first occurrence). Only change the values in the last column (second occurrence).
---------- Post updated at 01:59 PM ---------- Previous update was at 01:57 PM ----------
Quote:
Originally Posted by vgersh99
something to start with:
I am looking for steps in VI editor not sed command.
Hello All,
I have a string "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031", and I just want to extract LLSV1, but I dont get the expected result when using the sed command below.
# echo "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031" | awk '{print... (4 Replies)
Hi
i want to search two pattern on same line and replace onther pattern..
INPut file
aaaa bbbbb nnnnnn ttttt
cccc bbbbb nnnnnn ppppp
dddd ccccc nnnnnn ttttt
ffff bbbbb oooooo ttttt
now i want replace this matrix like.. i want search for "bbbbb","nnnnnn" and search and replace for... (4 Replies)
Hi,
i want to remove a certain pattern when i type pwd.
pwd will look like this:
..../....../....../Pat_logs/..../....../...../......
the dotted lines are just random directory names,
i want it to remove the "Pat_logs/...../....../....../" part
so for example:
... (8 Replies)
I need this.
aaa
OOOOO
bbb
ccc
OOOOO
ddd
fff
ggg
OOOOO
iii
OOOOO
I need all OOOOO replaced with PPPPP, but only change after the pattern ggg. So the first two OOOOO should not be changed.
OUTPUT should be :-
aaa (2 Replies)
I have a pattern
username:x:32005:32006::/usr/local/user:/bin/bash
I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell
So it becomes
username:x:32005:32006::/usr/local/user:/usr/local/my/bin/noshell (7 Replies)
Hi,
I have a requirement where I need to replace a string in a line and this line will be identified by search criteria on previous line:
E.g.:
I have an xml file and Contents as below:
<Root>
<NameValue>
<name>Global/Text/Data</name>
<value>This is valid... (14 Replies)
Hi, I am a rookie of Linux.
I have a problem on how can I replace a certain pattern in Linux with nothing. Can anyone help me?:(
sample.txt:
<binding>App189
ABC SampleMachine1 ABC
XXX
YYY
ZZZ
</binding>
<binding>App190
ABC SampleMachine2 ABC
XXX
YYY
ZZZ
</binding>
<binding>App191... (3 Replies)
Hi,
Need help to extract a pattern using sed or cut or any other means.
Input
'name1',1234567890
'name2',2222222222
'name3',3333333333
Expected output
name1,1234567890
name2,2222222222
name3,3333333333 (3 Replies)
Hi experts, I'm looking for a unix solution to replacing "NA" within a matrix with the mean of the column:
$cat file
ID a b c d
day 10 5 100 50
cat 20 6 200 50
dog NA 8 NA 50
car 15 NA NA ... (3 Replies)
Not able to paste my content. Please see the attachment :-( (2 Replies)
Discussion started by: vivek d r
2 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)