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Top Forums Shell Programming and Scripting Concatenate small line with next line perl script Post 302872773 by Ophiuchus on Sunday 10th of November 2013 01:07:38 AM
Old 11-10-2013
Concatenate small line with next line perl script

Hello to all,

I'm new to perl, I have input file that contains the string below:
Code:
315350535ff450000014534130101ff4500ff45453779ff450ff45545f01ff45ff453245341ff4500000545000

This string has as line separator "ff45". So, I want to print each line but the code below is not working.
Code:
perl -pe '
local $/;
$/ = "ff45";
while (<FILE>){
    print;
}' file

If the only condition is set as line separator "ff45", the output would be:
Code:
315350535ff45
0000014534130101ff45
00ff45
453779ff45
0ff45
545f01ff45
ff45
3245341ff45
00000545000

But when the line length is less than 7 I want to concatenate that small line with the next one,
So, the final output I'd like to get is below (red part is small line, in blue next line):
Code:
315350535ff45
0000014534130101ff45
00ff45453779ff45
0ff45545f01ff45
ff453245341ff45
00000545000

May you help me in how to get this.

PS: If possible, I'd like only to modify the code inside the while loop, since I want to incorporate as part of a bigger script.

Thanks in advance.
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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