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Top Forums Shell Programming and Scripting Reading in 4th number in a line Post 302871547 by pina on Wednesday 6th of November 2013 11:17:55 AM
Old 11-06-2013
[Solved] Reading in 4th number in a line

I'd like to read a file (mydata.dat) line by line. The file consists of 5 columns filled with numbers, like so:
Code:
    83.018     1.953    49.587   20550.000  353
    83.213     1.953    49.195   20600.000  171
    84.935     1.954    48.803   20650.000  920

For every read line (i.e. in every step of the loop), I'd like to read the 4th number in that line (e.g. 20550.000 in the first line above) into a variable arg4. The first, second and third numbers (e.g. 83.018, 1.953, 49.587) I'd like to write to a file (outfile_${arg4}) whose name should contain the 4th number.

E.g. file 'outfile_20550.000' contains
Code:
83.018     1.953    49.587

This is what I came up with, but it doesn't work yet..
Code:
while read line;
do      
      arg4=`echo  | awk '{ print $4 }' $line`
      echo | awk `{ print $1, $2, $3 }` $line >> outfile_${arg4}   

done < mydata.dat

Moderator's Comments:
Mod Comment Please use code tags for your data and code next time Smilie
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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