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Full Discussion: Problem with find
Top Forums Shell Programming and Scripting Problem with find Post 302871347 by CarloM on Wednesday 6th of November 2013 03:28:10 AM
Old 11-06-2013
Quote:
Originally Posted by tempestas
IAm=${0##*/}
I have never seen this. If I echo $IAm the output is the name of the script that is called by the list, i.e. "rename.sh". What are the ##*/ meaning? 0 marks the argument from the list, right?
http://tldp.org/LDP/abs/html/paramet...stitution.html.

${var##pattern} and ${var%%pattern} remove the matching pattern from the left and right (respectively) of var. ${var:pos:len} gives len characters of var starting from index pos.

Quote:
The other thing I don't get are the exits exit 2; exit 3; exit 4. Why are they numbered?
Anything non-zero is failure (usually), but different codes let you implement different handling for specific errors when you check the return value of the script.
 

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