1. Shell Programming and Scripting

Solaris 10 doesn't seem to like me a lot. I am trying to run a simple script to accept date and return epoch of that date: #!/usr/bin/perl -w use strict; use Time::ParseDate; my($date1)="Mon Mar 27 05:54:08 CDT 2009"; chomp $date1; #Convert to seconds since start of epoch my $time1 =... (3 Replies)

2. Shell Programming and Scripting

Hi all! I have a "simple" problem: I want to convert a date and time string (YYYYMMDDhhmmss) to epoch (unix time) in a shellscript. I want to use the "date/time" string as an input to the script, eg: scriptname.sh 20090918231000 and get the epoch format echoed out. Is there an... (3 Replies)

3. Shell Programming and Scripting

System: HP-UX Kornshell Perl is installed, but not POSIX Hello, I am calculating a future date/time. To do this I take the system date in epoch format and add to it. I now need to take the new epoch date and convert it to MMDDYYHHmm format. Any help with this is greatly appreciated. (4 Replies)

4. Shell Programming and Scripting

Could someone please explain how to get a formatted date from the unix epoch (the number of seconds since Jan 1, 1970) For example., If the input is 1297969816, then the output should be 2011-02-17 in YYYY-MM-DD formatted manner. I am using AIX sh shell. Tried date -d and date --date, these... (4 Replies)

5. Shell Programming and Scripting

I am trying get time difference of two dates in secs. Initially I want to convert a standard date format to epoch for two dates and then subtract the two epoch dates. Example : date -d "2007-09-01 17:30:40" '+%s' But this gives me below error date: illegal option -- d Usage: date OS: AIX... (6 Replies)

6. Programming

Hi all , I need to know how to convert a time stamp entered by the user to be converted to GMT/UTC(epoch time) using mktime() and gmtime() for exapample the input will be put in the form ptm.tm_sec = 0; ptm.tm_min = 59; ptm.tm_hour = 11; ptm.tm_mday = 20;... (2 Replies)

7. OS X (Apple)

Hi all, In terminal when I enter: date -j -f date -j -f "%Y/%m/%d %T" "2011/09/30 13:00:00" +"%s" The output is: When I put 2011/09/30 in var A, and I subsequently enter: date -j -f date -j -f "%Y/%m/%d %T" "${A} 13:00:00" +"%s" The output is: (10 Replies)

8. Shell Programming and Scripting

Need assistance in converting an epoch time to Julian date To get epoch perl -e 'use Time::Local; print timelocal(1,5,2,12,10,2008), "\n"' (3 Replies)

9. Shell Programming and Scripting

so i have to perform a certain task at set times. for instance, i need to run a job at 12:30am every night, and other jobs, i only need to have them run on saturdays. how do i manipulate the date command to give me the epoch equivalence of what 12:30am would be every day? im looking for a... (3 Replies)

10. Shell Programming and Scripting

I am not able to pass date stored in a variable as an argument to date command. I get current date value for from_date and to_date #!/usr/bin/ksh set -x for s in server ; do ssh -T $s <<-EOF from_date="12-Jan-2015 12:02:09" to_date="24-Jan-2015 13:02:09" echo \$from_date echo... (7 Replies)