Turning given date to epoch

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# 1  
Old 10-29-2013
Turning given date to epoch

i can probably script this in bash, but, i was wondering, does anyone know of a simple way to translate a given time to epoch?

date -d@"29/Oct/2013:17:53:11"

the user would specify the date: 29/Oct/2013:17:53:11

and the script will simply interpret that to epoch: 1348838383 (this is just an example)
# 2  
Old 10-29-2013
local to epoch
$ date -d"2013-10-29 17:53:11" +%s

epoch to local
$ date -d@1348838383
Fri Sep 28 18:49:43 IST 2012

# 3  
Old 10-29-2013
Or if you have ksh93, use builtin printf %T option:

printf "%(%s)T" "29/Oct/2013:17:53:11"

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# 4  
Old 10-29-2013
date --date="$(echo "29/Oct/2013:17:53:11" | sed -e 's/\// /g;s/:/ /')" +%s

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# 5  
Old 10-29-2013
To use -d date option you will need to replace slash with hyphen and get rid of colon between year and hour something like this in bash:

$ D="29/Oct/2013:17:53:11"
$ D=${D//\//-}
$ date -d "${D/:/ }" +%s

This User Gave Thanks to Chubler_XL For This Post:
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