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Full Discussion: Wildcard search in if loop
Top Forums Shell Programming and Scripting Wildcard search in if loop Post 302866075 by rbatte1 on Monday 21st of October 2013 07:46:30 AM
Old 10-21-2013
greet_sed, you will notice that kumaar1986 is in the Bourne Shell, so your statement is not valid.

As a demo with my version (and using a case statement to neaten the options):-
Code:
$ ls       
abc1216    abc124     abckwefn   xyz116     xyz125     xyzwefwef
abc123     abc125     demo       xyz124     xyz129
$ cat demo 
#!/bin/sh
echo "\n\nSimple if\n"
for file in abc* ghi* xyz*
do
   testval="${file%${file##???}}"  
   if [ "$testval" = "abc" ];
   then
      echo "Found abc file $file"
   fi
   if [ "$testval" = "ghi" ];
   then
      echo "Found ghi file $file"
   fi
   if [ "$testval" = "xyz" ];
   then
      echo "Found xyz file $file"
   fi
done

echo "\n\nUsing a CASE statement\n"
for file in abc* ghi* xyz*
do
   testval="${file%${file##???}}"
   case "$testval" in
     abc) echo "Found abc file $file"   ;;
     ghi) echo "Found ghi file $file"   ;;
     xyz) echo "Found xyz file $file"   ;;
     *)   echo "Found other file $file" ;;
   esac
done

$ demo     


Simple if

Found abc file abc1216
Found abc file abc123
Found abc file abc124
Found abc file abc125
Found abc file abckwefn
Found xyz file xyz116
Found xyz file xyz124
Found xyz file xyz125
Found xyz file xyz129
Found xyz file xyzwefwef


Using a CASE statement

Found abc file abc1216
Found abc file abc123
Found abc file abc124
Found abc file abc125
Found abc file abckwefn
Found other file ghi*
Found xyz file xyz116
Found xyz file xyz124
Found xyz file xyz125
Found xyz file xyz129
Found xyz file xyzwefwef
$

You will notice that in the second part, the file ghi* seems to be listed. This is probably because it's actually getting a message about file not found, hence why having the *) clause for the case statement is a good idea. You may want to eith handle the error, ignore it or notify that expected input is missing.




Robin
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