Sponsored Content
Full Discussion: Format output using awk
Top Forums Shell Programming and Scripting Format output using awk Post 302864613 by RavinderSingh13 on Wednesday 16th of October 2013 10:02:04 PM
Old 10-16-2013
Quote:
Here is an awk solution:



Code:
awk 'NF==8{DEV[++L]=$1}NF==7{$0=DEV[L]" "$0}NF==8{POOL[$8];P[$1,$8]=$5}END { printf "DEV" for(p in POOL) printf "%s", (i++ ? "%:" : ",") p printf "\n" for(i=1;i<=L;i++) { printf "%s", DEV[i] f=0 for(p in POOL) printf "%s", (f++ ? ":" : ",") P[DEV[i],p]+0 printf "\n" }}' infile
Hello Chubler_XL,

Could you please explain it, we will be grateful to you.


Thanks,
R. Singh
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Output in a particular format using AWK

Hi All, I am trying to check if if column 5 is greater than 90. If greater it will print the term in column 6, else if all are within limit, then it will output "Size is within limit". I can't seem to do that with the below code. The output should only be 1 statement of "Size is within the... (4 Replies)
Discussion started by: Raynon
4 Replies

2. Shell Programming and Scripting

[need help] output format from awk

hi all, i have a problem with my nawk command output below is the description : nawk $12 == "00008001" { cnt++;cs_cd } END {for(cd in cs_cd) print cd, cs_cd } 2007020814.TDR output : 133 123 desire output: 133,123,.... please advices thank you so much (6 Replies)
Discussion started by: bucci
6 Replies

3. Shell Programming and Scripting

Awk output format help!!! Urgent!!!!

Hello!! I am capturing and counting certain uniq occurance of certain evet from large log files. below is my output I m getting with my script: No of Messages Date Hour 150 Aug15 1 234 Aug15 2 345 Aug15 3 . ... (4 Replies)
Discussion started by: namodi
4 Replies

4. Shell Programming and Scripting

scripting/awk help : awk sum output is not comming in regular format. Pls advise.

Hi Experts, I am adding a column of numbers with awk , however not getting correct output: # awk '{sum+=$1} END {print sum}' datafile 2.15291e+06 How can I getthe output like : 2152910 Thank you.. # awk '{sum+=$1} END {print sum}' datafile 2.15079e+06 (3 Replies)
Discussion started by: rveri
3 Replies

5. Shell Programming and Scripting

awk - format output

Input file1 zone: BAU_SERVER1 C0:50:76:01:C6:20:00:12; 50:06:01:69:3B:20:14:8B; 50:06:01:60:3B:20:14:8B zone: BAU_SERVER2 C0:50:76:01:C6:20:00:08; 50:06:01:69:3B:20:14:8B; 50:06:01:60:3B:20:14:8B zone: ... (4 Replies)
Discussion started by: greycells
4 Replies

6. Shell Programming and Scripting

awk to format an output

awk experts, I have in put file with time stamp followed by "," separated data. same patern continues. The output need time stamp in first columns and data total in 2nd columns. Input file T 9:15 d0,1,3,3 d1,2,1,1 d2,3,1,5 e1,1,1,1 T 9:30 d0,1,1,1 d1,2,3,2 d3,1,2,1... (10 Replies)
Discussion started by: arv_cds
10 Replies

7. UNIX for Dummies Questions & Answers

after awk-> format output

hi i have a awk command with several querys.... awk 'FS="|""; print $4, $5, $6...etc.... $4 gives me the date 20120304 $5 is timestamp 101023 I want to format these in 2012.03.04 or 2012/03/04 10:10:23 but have no idea, if this is possible with format-parameters in the awk... (2 Replies)
Discussion started by: Jazzmatazz
2 Replies

8. Shell Programming and Scripting

Using AWK to format output and email

Hello, I'm a bit stumped, for some reason when using AWK 'print' is not printing the entire date/line. awk '{print "Ticket #: " $1} {print "Queue : " $2} {print "Recieved : " $3} {print "AP Date : " $4} {print "Circuit ID : " $5} {print... (4 Replies)
Discussion started by: ArvinSodhi
4 Replies

9. Shell Programming and Scripting

Format output in AWK command

hi Friends , I have a file as below s.txt 1~2~~4 2~6~~7 3~8~~9 t.txt 1~2~~4 2~5~8~7 3~8~~7 header for both files is common (2 Replies)
Discussion started by: i150371485
2 Replies

10. Shell Programming and Scripting

Need to maintain in- and output format with awk

Hi All, I have a data file (myfile.txt) as below: - A H C - A HHH F - AAA HH I The importan point is that the width between the columns are not fixed and the column seperator is space. I wish to change the value of 4th column using awk only when $3 = HH. I can... (4 Replies)
Discussion started by: angshuman
4 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:25 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy