Hi,
In the following bash code rather than cutting at a predefined character I would like to cut at position i (i var from loop).
Is this possible? I have tried eval, but either it's not possible or my syntax is wrong.
thanks
Nick
for i in {1..9}
do
theChar=$(echo... (3 Replies)
I have a function "MyPrint" that runs great on a file (BaseData.txt) that has one line of data. If i add rows to the text file it's reading the tFile variable becomes a list of every field 2 in the file. To correct this, i tried to call the function from a loop where i read one line at a time and... (4 Replies)
Hi Forum
Im having problem with cut it even when i cut a field from an input file
eg
echo $x | cut -f1 -d':'
it doesnt read the whole line if there is a space in it
eg
thisLineHasA SpaceInIt
:wall:
it only read up to the space.What i want is so the it cut the field as one line ... (8 Replies)
Hi
Can anyone what I am doing wrong while using cut command.
for f in *.log
do
logfilename=$f
Log "Log file Name: $logfilename"
logfile1=`basename $logfilename .log`
flength=${#logfile1}
Log "file length $flength"
from_length=$(($flength - 15))
Log "from... (2 Replies)
Hello,
I'm using cygwin on my Windows 7 machine.
From the man pages of cut:
--output-delimiter=STRING
use STRING as the output delimiter the default is to use the input delimiter
I tried the following commands and got the error messages:
$ cut -c1-10,20-30 -d... (10 Replies)
I'm a complete beginner in UNIX (and not a computer science student either), just undergoing a tutoring course. Trying to replicate the instructions on my own I directed output of the ls listing command (lists all files of my home directory ) to My_dir.tsv file (see the screenshot) to make use of... (9 Replies)
Hi,
i have a source file and have 3 columns and separated by "|" .i want to split this 3 columns in different variable.When i am executing this values indivisually giving correct result but when the same execute inside a for loop,it's giving issues.
Src file(jjj.txt)
-------... (8 Replies)
HI Folks -
I'm very frustrated - I'm trying to execute a verys imple for loop and rename the files if they exist.
here is my loop :
ydate=`TZ=aaa24 date +%m%d`
CR_YR=$(date "+%Y")
echo $ydate
echo ${CR_YR}
cd... (6 Replies)
OS : RHEL 6.8
Shell : bash
I want to remove all lines like below from the history output as it has password.
$ history | grep sqlplus
239 sqlplus jn_usr/dxc825#@10.5.12.106/OCSGPD
256 sqlplus osb_soa/KD1egM09@10.5.12.196/BSOAPRD
279 sqlplus jn_usr/dxc825#@10.80.16.219/OCSGPD... (5 Replies)
Discussion started by: John K
5 Replies
LEARN ABOUT HPUX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)