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Top Forums Shell Programming and Scripting Incrementing parts of ten digits number by parts Post 302861947 by Natalie on Thursday 10th of October 2013 01:45:19 AM
Old 10-10-2013
Incrementing parts of ten digits number by parts

I have number in file which contains date and serial number:
2013101000.

The last two digits are serial number (00). So maximum of serial number is 100.

After reaching 100 it becomes 00 with incrementing 10 which is day with max 31.

after reaching 31 it becomes 00 and increments 10 which is month with maximum 12.

so basically when I run code it rewrites 10 digits with above conditions... My problem is that I dont know how to separate these 4 numbers. If I have "." or smth like that among them then it would be easier but here I have no idea.....

So example:
cat file
2013113098

sh my_code
cat file
2013113099

sh my_code
cat file
2013113100

sh my_code
cat file
2013113101

then I sh my_code 100 times
cat file
2013120100

Moderator's Comments:
Mod Comment Next time, please use code tags for your code and data!

Last edited by vbe; 10-10-2013 at 12:06 PM..
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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