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Full Discussion: Verification on shell script
Top Forums Shell Programming and Scripting Verification on shell script Post 302855715 by nimafire on Friday 20th of September 2013 03:18:42 PM
Old 09-20-2013
Quote:
Originally Posted by vbe
I get the point of the thread owner..., what I dont understand is since he knows who are allowed ( IP list...) why not test if you are allowed to download?
mm i want to publish my script so i need verification method to know who use this script
i have not find any solution to encode-decode shell scripting so i use ip restriction by allow and deny

---------- Post updated at 02:18 PM ---------- Previous update was at 02:12 PM ----------

Quote:
Originally Posted by gacanepa
I insist that checking the existence of a file is not the best way to allow or deny its execution.
What I would do is wget the file, then if that command completed successfully I'd start the download operation, otherwise I'd show the error message, more like so:
Code:
wget $MIRROR/pack76.sh
	if [ $? == 0 ]
	then
		sh pack76.sh
	else
		echo -e "$RED The download cannot be performed $RESET"
	fi

Hope it helps.
good idea
so shell scripting do not have any protection like i need?
so what shell programmer do?
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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