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Top Forums Shell Programming and Scripting Parsing log file for last 2 hours Post 302853603 by RudiC on Sunday 15th of September 2013 01:28:34 PM
Old 09-15-2013
You did not mention what you have tried so far, which should become a good habit so you can improve yourself.

But, as this task is soooo easy, here we go:
Code:
grep -E "Sep 15 (06|07)" file
Sep 15 06:46:05 servername
Sep 15 06:46:05 servername
Sep 15 06:41:33 servername
Sep 15 06:46:05 servername
Sep 15 07:46:05 servername
Sep 15 07:41:33 servername
Sep 15 07:46:05 servername

 

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SA2(8)								Linux User's Manual							    SA2(8)

NAME
sa2 - Write a daily report in the /var/log/sa directory. SYNOPSIS
/usr/lib/sa/sa2 DESCRIPTION
The sa2 command is a shell procedure variant of the sar command which writes a daily report in the /var/log/sa/sardd file, where the dd parameter indicates the current day. The sa2 command handles all of the flags and parameters of the sar command. The sa2 command is designed to be started automatically by the cron command. EXAMPLES
To run the sa2 command daily, place the following entry in your root or adm crontab file: 5 19 * * 1-5 /usr/lib/sa/sa2 -A & This will generate a daily report called /var/log/sa/sardd It will also remove reports more than one week old. FILES
/var/log/sa/sardd Indicate the daily report file, where the dd parameter is a number representing the day of the month. AUTHOR
Sebastien Godard <sebastien.godard@wanadoo.fr> SEE ALSO
sar(1), sadc(8), sa1(8), mpstat(1), iostat(1), vmstat(8) http://perso.wanadoo.fr/sebastien.godard/ Linux DECEMBER 1999 SA2(8)
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