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Full Discussion: Parse User Logon Count
Top Forums UNIX for Dummies Questions & Answers Parse User Logon Count Post 302852311 by brabored on Wednesday 11th of September 2013 08:04:50 AM
Old 09-11-2013
Parse User Logon Count

Hey,

My access.log for one application is not rolled over.

I would like to get users count.

Right now I am doing
Code:
cat logon.list | grep 2013-09-11| |grep Succeeded | wc -l

Since the file doesnt rotate out I have to grep for new date/
I tried to specify DATE=date "+DATE: %Y-%m-%d" in a script but grep string isnt correctly done.

How to get awk to pick the latest data and grep and wc-l out latest user logons?

Thanks,

Last edited by vbe; 09-11-2013 at 10:08 AM.. Reason: code tags...
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep is used to invoke the grep on compress'ed or gzip'ed files. All options specified are passed directly to grep. If no file is speci- fied, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If zgrep is invoked as zegrep or zfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. For example: for sh: GREP=fgrep zgrep string files for csh: (setenv GREP fgrep; zgrep string files) AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), egrep(1), fgrep(1), zdiff(1), zmore(1), znew(1), zforce(1), gzip(1), gzexe(1) ZGREP(1)
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