Sponsored Content
Top Forums Shell Programming and Scripting [Solved] FOR loop / IF statement returning error Post 302848901 by vbe on Friday 30th of August 2013 10:27:03 AM
Old 08-30-2013
Because you cant use $? like that...
Code:
        let DID=$?
        echo DID: $DID
        #let DID=1
        [ $DID != 0 ] && echo "echo failed"
        echo DID: $DID

I set DID to 1 so to see your condition work... in other words your script will run with DID=0 always since the command producing the result of it ($?) at that point is successful...
I know Im not very clear but its friday...

So your script now :
Code:
for NUM in 1 2 3
do
    echo $NUM
    for LET in A B C
    do
        echo $LET
        let DID=$?
        echo DID: $DID
        [ $DID != 0 ] && echo "echo failed"
        echo $?
    done
done


Last edited by vbe; 08-30-2013 at 11:30 AM.. Reason: added modified script
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

For loop statement - catch error

I'm having a question about for loops. (bash) I have the following for example: for file in `ls *.txt` do read file ... done Now when there is a file present there is no problem, now when there is no file present I get the following output in my standard mail box : "No such... (4 Replies)
Discussion started by: lumdev
4 Replies

2. UNIX for Dummies Questions & Answers

Loop on array variable returning error: 0 not found

I'm guessing i have a syntax error. I'm not sure it get's past the the while condition. I get an error 0 not found. Simple loop not sure what I'm doing wrong. #!/usr/bin/ksh set -A MtPtArray /u03 /u06 tUbound=${#MtPtArray } echo $tUbound i=0 while ($i -lt $tUbound) do print... (4 Replies)
Discussion started by: KME
4 Replies

3. UNIX for Dummies Questions & Answers

For loop returning more values

Hi All, Thanks all of you for the help you provide to me. Well, I have one more problem, where I am trying to pull file system information in the loop and display the filesystem percentege. I am using following code to achive this, nut it's giving the weired output. My file system is ... (1 Reply)
Discussion started by: alok.behria
1 Replies

4. UNIX for Dummies Questions & Answers

[Solved] Syntax error for awk in a loop

can some one please tell me what is the problem with my syntax:confused: I have 100 files in one folder 1. want to read each of the line by line 2. calculate their number of the words between the first word and the last word of each line 3. create file for each file with number of words... (8 Replies)
Discussion started by: A-V
8 Replies

5. Shell Programming and Scripting

for loop with internal unix command in statement throwing error

Hi I've gotten a plugin script that won't run. I keeps throwing an error at the following line. for BARCODE_LINE in `cat ${TSP_FILEPATH_BARCODE_TXT} | grep "^barcode"` do #something done The error reads ... (3 Replies)
Discussion started by: jdilts
3 Replies

6. Shell Programming and Scripting

[SOLVED] Problem in wait statement

Iam having a script which is used to load users and dumpfile in any given schema.Iam trying to autolog the script and have added two fucntion in it. function init_stdout_redirect { OUT_LOG=$1 OUT_PIPE=$(mktemp -u) # Create the output pipe mkfifo $OUT_PIPE # Save stdout and... (15 Replies)
Discussion started by: Vikram_Tanwar12
15 Replies

7. Shell Programming and Scripting

[Solved] 0403-057 Syntax error for if statement

I am getting the following error when I am running a script in ksh when trying to execute an if statement comparing two numerical values tstmb.sh: 1.5321e+08: 0403-057 Syntax error Below is my code snippet. #!/bin/ksh set -x TODAY=$(date +%y%m%d) for file in $(ls -rt *.log | tail... (11 Replies)
Discussion started by: kiran1112
11 Replies

8. Shell Programming and Scripting

[Solved] While loop error when add sqlplus command

Hi gurus, I hit a block when write the script. I need do while loop, in the loop I have code below. sqlplus -s abc/abc@abc <<EOF spool testwhile select * from dual; spool off exit; EOF when I run script with only this code, it works fine. if I add code as below: #!/bin/ksh ... (5 Replies)
Discussion started by: ken6503
5 Replies

9. Shell Programming and Scripting

[Solved] If statement in bash

I have the following code in bash, however "set red frmt" is not displayed. echo "iarg_rd = $iarg_rd" iarg_rd="2" if ; then echo "Hello World" fi if ; then frmt="${gap}${!frmt_titl_yl}" elif ; then frmt="${gap}${!frmt_titl_bk}" elif ; then echo... (2 Replies)
Discussion started by: kristinu
2 Replies

10. Shell Programming and Scripting

Statement returning error only launching the sh script via crontab

hi all, I created a sh script to import some tables from mysql to hive. No problem launching it manually, but if I schedule via crontab it returns me an error in the following part: #create an array containing all the tables for $dbname query="SELECT table_name FROM information_schema.tables'... (10 Replies)
Discussion started by: mfran2002
10 Replies
ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
All times are GMT -4. The time now is 08:44 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy