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Top Forums Shell Programming and Scripting [Solved] FOR loop / IF statement returning error Post 302848857 by jfxdavies on Friday 30th of August 2013 08:40:34 AM
Old 08-30-2013
[Solved] FOR loop / IF statement returning error

The code at the bottom is a simplified example of what we have.

If I use the following:
Code:
 [ $? != 0 ] && echo "echo failed"

$? returns 1

When I use
Code:
if [ $? != 0 ] ; then  echo "echo failed" ; fi

$? returns 0

Does anyone know what's wrong with this?

Using AIX 6.1 and KSH

Code:
for NUM in 1 2 3
do
    echo $NUM
    for LET in A B C
    do
        echo $LET
        [ $? != 0 ] && echo "echo failed"
        echo $?
    done
done

Thankyou.

Last edited by Scott; 08-30-2013 at 12:17 PM.. Reason: More code tags
 

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DATEFMT_IS_LENIENT(3)							 1						     DATEFMT_IS_LENIENT(3)

IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public bool IntlDateFormatter::isLenient (void ) DESCRIPTION
Procedural style bool datefmt_is_lenient (IntlDateFormatter $fmt) Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient. EXAMPLES
Example #1 datefmt_is_lenient(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'dd/mm/yyyy' ); echo 'lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } datefmt_set_lenient($fmt,false); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, "dd/mm/yyyy" ); echo "lenient of the formatter is : "; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0){ echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } $fmt->setLenient(FALSE); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> The above example will output: lenient of the formatter is : TRUE Trying to do parse('35/13/1971'). Result is : -2147483 Now lenient of the formatter is : FALSE Trying to do parse('35/13/1971'). Result is : Error_msg is : Date parsing failed: U_PARSE_ERROR Error_code is : 9 SEE ALSO
datefmt_set_lenient(3), datefmt_create(3). PHP Documentation Group DATEFMT_IS_LENIENT(3)
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