I'm having a question about for loops. (bash)
I have the following for example:
for file in `ls *.txt`
do
read file ...
done
Now when there is a file present there is no problem, now when there is no file present I get the following output in my standard mail box : "No such... (4 Replies)
I'm guessing i have a syntax error. I'm not sure it get's past the the while condition. I get an error 0 not found. Simple loop not sure what I'm doing wrong.
#!/usr/bin/ksh
set -A MtPtArray /u03 /u06
tUbound=${#MtPtArray
}
echo $tUbound
i=0
while ($i -lt $tUbound)
do
print... (4 Replies)
Hi All,
Thanks all of you for the help you provide to me. Well, I have one more problem, where I am trying to pull file system information in the loop and display the filesystem percentege. I am using following code to achive this, nut it's giving the weired output.
My file system is
... (1 Reply)
can some one please tell me what is the problem with my syntax:confused:
I have 100 files in one folder
1. want to read each of the line by line
2. calculate their number of the words between the first word and the last word of each line
3. create file for each file with number of words... (8 Replies)
Hi
I've gotten a plugin script that won't run. I keeps throwing an error at the following line.
for BARCODE_LINE in `cat ${TSP_FILEPATH_BARCODE_TXT} | grep "^barcode"`
do
#something
done
The error reads
... (3 Replies)
Iam having a script which is used to load users and dumpfile in any given schema.Iam trying to autolog the script and have added two fucntion in it.
function init_stdout_redirect {
OUT_LOG=$1
OUT_PIPE=$(mktemp -u)
# Create the output pipe
mkfifo $OUT_PIPE
# Save stdout and... (15 Replies)
I am getting the following error when I am running a script in ksh when trying to execute an if statement comparing two numerical values
tstmb.sh: 1.5321e+08: 0403-057 Syntax error
Below is my code snippet.
#!/bin/ksh
set -x
TODAY=$(date +%y%m%d)
for file in $(ls -rt *.log | tail... (11 Replies)
Hi gurus,
I hit a block when write the script.
I need do while loop, in the loop I have code below.
sqlplus -s abc/abc@abc <<EOF
spool testwhile
select *
from dual;
spool off
exit;
EOF
when I run script with only this code, it works fine.
if I add code as below:
#!/bin/ksh
... (5 Replies)
I have the following code in bash, however "set red frmt" is not displayed.
echo "iarg_rd = $iarg_rd"
iarg_rd="2"
if ; then
echo "Hello World"
fi
if ; then
frmt="${gap}${!frmt_titl_yl}"
elif ; then
frmt="${gap}${!frmt_titl_bk}"
elif ; then
echo... (2 Replies)
hi all,
I created a sh script to import some tables from mysql to hive.
No problem launching it manually, but if I schedule via crontab it returns me an error in the following part:
#create an array containing all the tables for $dbname
query="SELECT table_name FROM information_schema.tables'... (10 Replies)
Discussion started by: mfran2002
10 Replies
LEARN ABOUT PHP
datefmt_is_lenient
DATEFMT_IS_LENIENT(3) 1 DATEFMT_IS_LENIENT(3)IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::isLenient (void )
DESCRIPTION
Procedural style
bool datefmt_is_lenient (IntlDateFormatter $fmt)
Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly.
PARAMETERS
o $fmt
- The formatter resource.
RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient.
EXAMPLES
Example #1
datefmt_is_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/mm/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt,false);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
"dd/mm/yyyy"
);
echo "lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0){
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : -2147483
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_set_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_IS_LENIENT(3)