Hi
I have a file with lots of line feeds and form feeds (page break). Need to replace last occurrence of form feed (created by - echo "\f" ) in the file with line feed.
Please advise how can i achieve this.
TIA
Prvn (5 Replies)
I have a file with varying record length in it. I need to reformat this file so that each line will have a length of 100 characters (99 characters + the line feed).
AU * A01 EXPENSE 6990370000 CWF SUBC TRAVEL & MISC
MY * A02 RESALE 6990788000 Y... (3 Replies)
Hi! I have been struggling with a large file that has stray end of line characters.
I am working on a Mac (Lion). I mention this only because I have been mucking around with fixing my problem using sed, and I have learned far more than I wanted to know about Unix and Mac eol characters.
I... (1 Reply)
Hi Guys,
I am having a set of date format files files where I am performing the below set of operations in the files . I Need to replace the last line value with specific date which is a pipe delimited file.
for egf1_20140101.txt
aa|aus|20140101|yy
bb|nz|20140101|yy
.
.... (19 Replies)
Hi forum,
Can you please help me understand how to look for and replace the below pattern (containing line breaks) and return a new result?
Rules: Must match the 3 line pattern and return a 1 line result.
I have found solutions with sed, but it seems that sed installed in my system is... (5 Replies)
As per requirement if column 2 is NULL then 'N' ELSE 'Y'.
I have written below awk code. But it is not replacing values for first line. :confused:
cat temp.txt
1|abc|3
1||4
1|11|c
awk -F'|' '{if($2==""){$2="N"}else{$2="Y"} print $0 } {OFS="|"} ' < temp.txt
1 Y 3 ... (4 Replies)
Hi Forum.
I have the following script that splits a large fixed-width file into smaller multiple fixed-width files based on input segment type.
The main command in the script is:
awk -v search_col_pos=$search_col_pos -v search_str_len=$search_str_len -v segment_type="$segment_type"... (8 Replies)
Hello,
Can someone please share a Simple AWK command to append Carriage Return & Line Feed to the end of the file, If the Carriage Return & Line Feed does not exist !
Thanks (16 Replies)
Hi,
I'm trying to get a line returned as is from the below input.csv file in Bash in Linux, and somehow I get an unexpected newline in the middle of my input.
Here's a sample line in input.csv
$> more input.csv
TEST_SYSTEM,DUMMY@GMAIL.COM|JULIA H|BROWN
And here's a very basic while loop... (7 Replies)
Discussion started by: ChicagoBlues
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)