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Full Discussion: Getline not working in awk
Top Forums Shell Programming and Scripting Getline not working in awk Post 302834331 by MadeInGermany on Thursday 18th of July 2013 05:35:02 PM
Old 07-18-2013
Like I said, replace the BEGIN by a main loop over the first file argument (file1).
The variable line becomes $0, and $1,$2 etc. are the fields of $0.
Further, awk does not accept if ... else if ... without deeper { nesting }. (This is unlike shell and C.)
I have replaced with next that directly jumps to the next cycle (next line).
I further have replaced the outer { braces } that allows to use implicit if.
Also awk does not accept a new line everywhere. Here is my result:
Code:
awk -F, -v p2preject="P2P_REJ.txt" '
  $2 ~ "[*,#]" || ( ($2 + 0) !~ "^[0,5,7,8,9]")  || length($2 + 0) <4 || ($2 !~ "^[0,5,7,8,9]") { P2PREJECTCDR[$0]; next }
  (length($6) == 13 || length($6) == 14 || length($6)==11) && !($6 ~ "^[A-Z,a-z]") { P2PREJECTCDR[$0]; next }
  $6 =="" && substr($2,1,4)=="0091" && substr($2 + 0,3,1) !~ "^[1,2,5,7,8,9]" { P2PREJECTCDR[$0]; next }
  $6 == "" && substr($2,1,2) == "00" && length($2) == "12" { P2PCDR[$1,$2,$3,$4,$5,$2 + 0,$7]; next }
  $6 == "" && substr($2,1,1) == "0" && length($2) == "11" { P2PCDR[$1,$2,$3,$4,$5,$2 + 0,$7]; next }
  $6 == "" && substr($2,1,3) == "+91" && length($2) == "13" { P2PCDR[$1,$2,$3,$4,$5,substr($2,2,12),$7]; next }
  $6 == "" && substr($2,1,2) == "91" && length($2) == "12" && (substr($2,3,1) ~ "^[5,7,8,9]") { P2PCDR[$1,$2,$3,$4,$5,$2,$7]; next }
  $5 != "" && $6 != "" { P2PCDR[$0]; next }
  $5 == "" && $6 != "" { P2PCDR[$0]; next }
  $6 == "" && length($2)<=10 && length($2 + 0) >= 4 { P2PCDR[$1,$2,$3,$4,$5,$2 + 0,$7]; next }
  { P2PREJECTCDR[$0] }
  END {
    for ( counter in P2PCDR ) print counter >> "P2P.txt"
    for ( counter in P2PREJECTCDR ) print counter >> p2preject
  }
' file1

This User Gave Thanks to MadeInGermany For This Post:
siramitsharma
 

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shtool-path

SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME

       shtool-path - GNU shtool command dealing with shell path variables

SYNOPSIS

       shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]

DESCRIPTION

       This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments.  It
       prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.

OPTIONS

       The following command line options are available.

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	   Supress output. Useful to only test whether a program exists with the help of the return code.

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	   Transform a forward path to a subdirectory into a reverse path.

       -d, --dirname
	   Output the directory name of str.

       -b, --basename
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       -m, --magic
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18-Jul-2008							   shtool 2.0.8 						SHTOOL-PATH.TMP(1)
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