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Top Forums Shell Programming and Scripting [solved] awk: return code from system() always 0 ?? Post 302831481 by vidyadhar85 on Thursday 11th of July 2013 04:51:53 AM
Old 07-11-2013
I might be wrong here..

system returns the exit status of the command thats executed.. since echo $? was the last command and exit staus was 0..

However it should have returned the exit status from script too not sure why its not the case

I hope you are trying something similar below?
Code:
 
 
vidya> cat vv
date
exit 120
vidya> awk 'BEGIN{a="vv";v=system(a" ; echo $?");print v}'
Thu Jul 11 10:51:14 CEST 2013
120
0

 

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DEP3CHANGELOG(1)					      General Commands Manual						  DEP3CHANGELOG(1)

NAME
dep3changelog - generate a changelog entry from a DEP3-style patch header SYNOPSIS
dep3changelog patch [patch ...] [options] [-- [dch_options]] DESCRIPTION
dep3changelog extracts the DEP3 patch headers from the given patch files and builds a changelog entry for each patch. If the patch author differs from the one detected from the DEBEMAIL, NAME, DEBEMAIL, or EMAIL environment variables, "Thanks to author <email>" is added to the changelog entry for that patch. Any bug-debian or bug-ubuntu fields are added as "Closes" to the changelog entry. The generated changelog entries are passed to debchange as an argument along with the given dch_options. OPTIONS
--help, -h Display a help message and exit successfully. --version Display version and copyright information and exit successfully. ENVIRONMENT
DEBEMAIL, EMAIL, DEBFULLNAME, NAME See the above description of the use of these environment variables. AUTHOR
Steve Langasek <vorlon@debian.org> SEE ALSO
debchange(1) DEBIAN
Debian Utilities DEP3CHANGELOG(1)
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