Assuming that you're using a common US keyboard, the above expression will find several characters that are on the keyboard including, but not limited to {, }, |, [, and ] and you have a few unneeded backslashes. The following is a more complete vi search command:

Code:

/[^][[:space:]0-9a-zA-Z~!@#$%^&*()_+`={}|\\;':"<>?,./-]

Using the above search command on the output from the OS X command man 7 ascii only matches backspace characters. If you would also like to skip backspace and other control characters, you could use:

Code:

/[^][[:space:][:cntrl:]0-9a-zA-Z~!@#$%^&*()_+`={}|\\;':"<>?,./-]

The order of most of these characters doesn't matter, but the first three characters in this expression have to be [^] to start a non-matching expression that excludes ] and the - needs to be the last character before the closing ] to exclude the minus sign. (Your expression seems to have excluded - as an accident because in ASCII the range expression &-\/ (or equivalently &-/) in a non-matching expression excludes &, ', (, ), *, +, ,, -, ., and / and you also exclude several of these characters individually.) Of course, the [:space:] and [:cntrl:] have to remain as these sequences in order, but they can appear anywhere within the bracket expression.