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UNIX for Dummies Questions & Answers
How convert space separated list to matched columns?
Post 302830539 by Manchesterpaul on Tuesday 9th of July 2013 05:20:24 AM
07-09-2013
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10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello,
Could someone please help me to convert a string(s) of comma separated values into space padded columns in .ksh?
ex.
10-21-2008,someword,blah,127.0.0.1,8,3
10-21-2008,randomword,ick,128.0.111.128,1,0
converted to
10-21-2008 someword blah 127.0.0.1 8... (6 Replies)
Discussion started by: WhotheWhat
6 Replies
2. Shell Programming and Scripting
Hi,
Plz help.
input line
1;20100403;400|2;20100403;4|3;20290903;400|4;20290903;0|5;20290903;0|9;20100304;0|10;20100304;0|11;20100402;0|18;20100304;0
expected output
1;20100403;400
2;20100403;4
3;20290903;400
4;20290903;0
5;20290903;0
9;20100304;0
10;20100304;0
11;20100402;0... (4 Replies)
Discussion started by: suresh3566
4 Replies
3. Shell Programming and Scripting
Dear all,
I have a file in this format (like a matrix)
- A B C .. X
A 1 4 2 .. 2
B 2 6 4 .. 8
C 3 5 5 .. 4
. . . ... .
X . . ... .
and want to convert it into a file with this format:
A A = 1
A B = 4
A C = 2
...
A X = 2
B A = 2
B B = 6
etc (2 Replies)
Discussion started by: TheTransporter
2 Replies
4. Shell Programming and Scripting
How do I loop thru space separated values in a variable?
I hate to use very complicated counter increment logic for this kind of simple problem.
Expected result(using ksh)
$>echo "aaa bbbb cccc" | <looping code here>
var=aaa
var=bbbb
var=cccc
$>echo "aaa bbbb cccc" | while IFS=" "... (12 Replies)
Discussion started by: kchinnam
12 Replies
5. UNIX for Dummies Questions & Answers
Hi,
I have a large number of files which are written as csv (comma-separated values).
Does anyone know of simple sed/awk command do achieve this?
Thanks!
---------- Post updated at 10:59 AM ---------- Previous update was at 10:54 AM ----------
Guess I asked this too soon. Found the... (0 Replies)
Discussion started by: lost.identity
0 Replies
6. Shell Programming and Scripting
Hi, I am converting a comma separated file to fixed field lenght and I am using that:
COLUMNS="25 24 67 26 39 63 20 34 35 14 397"
(
cat $indir/input_file.dat | \
$AWK -v columns="$COLUMNS" '
BEGIN {
FS=",";
OFS="";
split(columns, arr, " ");
}
{
for(i=1; i<=NF;... (5 Replies)
Discussion started by: apenkov
5 Replies
7. Shell Programming and Scripting
Hi,
I need to extract an info in $1 based on a matched pattern in $2,$3,$4, and $5.
The sample input file as follows:-
ID Pat1 Pat2 Pro1 use1
add41 M M M
add87 M M M M
add32 ... (16 Replies)
Discussion started by: redse171
16 Replies
8. Shell Programming and Scripting
Hi,
I am having a file say list1 with a output like below
jun 12 18:23
may 20 18:23
Now i want to pass the above two values into for loop,I have written a script like this.
#!/bin/bash
a=`cat list1`
for i in $a
do
echo "HI $i"
done
expected output:
HI jun 12 18:23 (3 Replies)
Discussion started by: sumanthupar
3 Replies
9. Shell Programming and Scripting
Hi,
I have a list of tables in a file.txt
C_CLAIM
C_HLD
C_PROVIDER
I want the output to be
'C_CLAIM','C_HLD','C_PROVIDER'
Currently I'm usin awk and getting output which is almost correct but still has minor defects
awk -vORS="','" '{ print $1 }' file.txt
The output of... (4 Replies)
Discussion started by: wahi80
4 Replies
10. Shell Programming and Scripting
Hi All,
Hope you are doing Great!!!.
Today i have came up with a problem to say exactly it was for performance improvement.
I have written code in perl as a solution for this to cut in specific range, but it is taking time to run for files thousands of lines so i am expecting
a sed... (9 Replies)
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LEARN ABOUT DEBIAN
datetime::format::epoch::unix
DateTime::Format::Epoch::Unix(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::Unix(3pm) NAME
DateTime::Format::Epoch::Unix - Convert DateTimes to/from Unix epoch seconds SYNOPSIS
use DateTime::Format::Epoch::Unix; my $dt = DateTime::Format::Epoch::Unix->parse_datetime( 1051488000 ); # 2003-04-28T00:00:00 DateTime::Format::Epoch::Unix->format_datetime($dt); # 1051488000 my $formatter = DateTime::Format::Epoch::Unix->new(); my $dt2 = $formatter->parse_datetime( 1051488000 ); $formatter->format_datetime($dt2); DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the Unix epoch. METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor. o new() Constructor of the formatter/parser object. It has no parameters. SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details. AUTHOR
Eugene van der Pijll <pijll@gmx.net> COPYRIGHT
Copyright (c) 2003 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. SEE ALSO
DateTime datetime@perl.org mailing list perl v5.10.1 2007-12-03 DateTime::Format::Epoch::Unix(3pm)