without needing to start us another process to run bc.
Since it is quite possible that this find will remove applications, libraries, and data files that are used every day but haven't changed in the last decade; be sure that you only run something like this after you have made a backup of every file that might be affected... (I would strongly suggest running this with "-exec rm {} \;" replaced by "-print" first as a sanity check on what will be removed!)
Are you really worried about 2 or 3 days when you're going back a decade?
Last edited by Don Cragun; 07-08-2013 at 03:27 PM..
Reason: Fix typo.
Hi all,
i have a simple question that i want to find out the 30 minutes older files and delete those files from the particular location(Folder)
Generally for this purpose used to retreive the files with "atime" command
For example: find and delete the 2 days older log files use this below... (2 Replies)
i have to delete files which are older than 15 days or more except the ones in the directory Current and also *.sh files
i have found the command for files 15 days or more older
find . -type f -mtime +15 -exec ls -ltr {} \;
but how to implement the logic to avoid directory Current and also... (3 Replies)
Hello - I have a folder that contains files from 2003 till 2010. I am trying to figure out a command that would seperate each years file and show me a count?
Even if i can find a command that would give me year by year count, thats good enough too.
Thanks (8 Replies)
I have to retain only 1 day files in my system an I have to delete all the other files which are older than 24 hrs. Please let me know the option I have to give in the find -mtime command. (3 Replies)
Hi All,
I am using below code to delete files older than 2 days. In case if there are no files, I should log an error saying no files to delete.
Please let me know, How I can achive this.
find /path/*.xml -mtime +2
Thanks and Regards
Nagaraja. (3 Replies)
Hi,
I need a command for deleting all the compress files *.Z that are older than the current date - 5 days. Basically I have a directory where daily I meet some back up files and I want to remove automatically the ones 5 days (or more) older than the current date. How can I write a 'rm' command... (1 Reply)
Discussion started by: Francy
1 Replies
LEARN ABOUT SUSE
time::seconds
Time::Seconds(3pm) Perl Programmers Reference Guide Time::Seconds(3pm)NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.12.1 2010-04-26 Time::Seconds(3pm)
07-08-2013
(I would strongly suggest running this with "-exec rm {} \;" replaced by "-print" first as a sanity check on what will be removed!)