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Top Forums Shell Programming and Scripting Extracting a portion of the filename Post 302822705 by kamal_p_99 on Tuesday 18th of June 2013 05:18:46 AM
Old 06-18-2013
Hi Pravin

I am thinking of using the sed command, but dont know how to go about it.

I have a script

Code:
for i in `ls *TEXTPATTERN*`;do grep String $i | wc -l | grep -v 0 | $i >> matchedfiles.txt;done

on the last $i I would like to just output a portion filenames for matched file.

Last edited by radoulov; 06-18-2013 at 07:53 AM..
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep is used to invoke the grep on compress'ed or gzip'ed files. All options specified are passed directly to grep. If no file is speci- fied, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If zgrep is invoked as zegrep or zfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. For example: for sh: GREP=fgrep zgrep string files for csh: (setenv GREP fgrep; zgrep string files) AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), egrep(1), fgrep(1), zdiff(1), zmore(1), znew(1), zforce(1), gzip(1), gzexe(1) ZGREP(1)
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