awk fatal:division by zero attempted bypass with a condtion Post: 302820389

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

error "awk: (FILENAME=- FNR=23) fatal: division by zero attempted"

Hi , I have file : after i run this command : there are error can we print blank line if output error ?? thanks.. ^^

2. Shell Programming and Scripting

awk error message: division by zero attempted

Hi, I'm executing unixbench tool v4.1 on an embedded system and I'm getting these error messages: Execl Throughput 1 2 3awk: /unixbench/unixbench-4.1.0/pgms/loops.awk:38: (FILENAME=- FNR=4) fatal: division by zero attempted Pipe Throughput 1 2 3 4 5 6 7 8 9 10awk:...

3. UNIX for Advanced & Expert Users

awk: division by zero

I received error "awk: division by zero" while executing the following statement. SunOS 5.10 Generic_142900-15 sun4us sparc FJSV,GPUZC-M echo 8 | awk 'END {printf ("%d\n",NR/$1 + 0.5);}' file1.lst awk: division by zero Can someone provide solution? Thanks Please use code...

4. Shell Programming and Scripting

awk division error - 0

input 0 0 9820373 2069 0 0 11485482 awk '{print ($1/$3) / ($4/$7)}' input error Is there any way to fix this problem ?

5. Shell Programming and Scripting

variables division with awk

hello i try to divide 2 variables in order to get a percentage--that's why i'm not interested in integer division--but nothing seems to work I think awk is suitable for this but i'm not quite sure how to use it.. any ideas? here's what I want to do: percentage = varA/varB thank you

6. Shell Programming and Scripting

awk - Division with condition

Hi Friends, I have an input file like this cat input chr1 100 200 1 2 chr1 120 130 na 1 chr1 140 160 1 na chr1 170 180 na na chr1 190 220 0 0 chr1 220 230 nd 1 chr2 330 400 1 nd chr2 410 450 nd nd chr3 500 700 1 1 I want to calculate the division of 4th and 5th columns. But, if...

7. Shell Programming and Scripting

Awk: cmd. line:1: fatal: division by zero attempted

when i try the snippet in the console its working fine: ps awwwux | grep php-fpm | grep -v grep | grep -v master | awk '{total_mem = $6 * 1024 + total_mem; total_proc++} END{printf("%d\n", total_mem / total_proc)}' output: but when i try the bash script: #!/bin/sh # -*- sh -*- #...

8. Shell Programming and Scripting

awk Division By Zero Bypass

Hi Friends, I don't understand why "a" is always being printed as zero, when I execute the following command. awk '{if($6||$8||$10||$12==0)a=b=c=d=0;else (a=$5/$6);(b=$7/$8);(c=$9/$10);(d=$11/$12); {print...

9. Shell Programming and Scripting

Division by zero attempted error during linear conversion of values between 0.25 to 1

I want to implement the below formula with awk oneliner new_value = ((old_value - old_min) / (old_max - old_min) ) * (new_max - new_min) + new_min I want to pass the value of old_min and old_min as variable. Here is what I did for this old_min=$(awk 'BEGIN{a=100000000000}{if ($10<0+a) a=$10}...

10. UNIX for Beginners Questions & Answers

Fatal division by zero attempted

Hello. I'm writing an awk script that looks at a .csv file and calculates the weighted grade based on the scores and categories in the file. I keep getting a fatal division by zero attempted error and I know what it means but I've been looking over the code for awhile and am not sure what is...

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)