Is it possible to grep for two files and assign their names to two separate variables with for loop? I am doing the below currently:
fname in the for loop here holds the name of the Ucountry_file. Likewise, in the same $dirA, there is another file called Rcountry_file. I want to grep for that as well and assign to another variable using the same for loop. Can it be done?
Hi,
I have some problem in assigning values to variables: This is what Iam literally doing:
i=0
input=test
temp$i = $input
In the sense, I try to assign the value in the variable input (ie., test) to another variable temp0 (since i is assigned 0, temp$i is temp0). Seems simple, but I get... (3 Replies)
I need to do something like this:
for i in 1 2 3 4 5; do
arr=$(awk 'NR="$i" { print $2 }' file_with_5_records)
done
That is, parse a file and assign values to an array in an ascending order relative to the number of record in the file that is being processed on each loop.
Is my... (2 Replies)
Hi
I am new to shell scripting and i am preparing a script.
for now i am work on a sub part of it..but i am unable to make it work.
---
the test code that i am working on
--------------------------
IFS=""
Sample_eve=`psg proc_s | grep tY`
n=0
for line in $Sample_eve... (41 Replies)
How do I assign values to reference variables?
I am assigning a variable name to --> $user_var
Then I am trying to change its underlying variable value by
$((user_var))=$user_value .. its failing,,
Please let me know if there is a way to do this dynamically..
FileA.props... (5 Replies)
Please help me to automatically assign the output of awk command to the variables cs3, cs4, cs5 and cs6 using a for loop. The below code is not working.
for i in 3 4 5 6
do
cs$i=`awk -F"|" 'BEGIN{sum=0}{sum=sum+$'$i'}END{printf("%d\n", sum)}' css`
done
echo $cs3 $cs4 $cs5 $cs6 (9 Replies)
Hi! This might be a simple thing, but I'm struggling to assign values to variables from the file.
I've the following values stored in the file.. It consists of only two rows..
10
20
I want to assign the first row value to variable "n1" and the second row value to variable "n2"..
That is ... (3 Replies)
Hi, I was wondering if anyone could assist me for (what is probably) a very straightforward answer.
I have input files containing something like
File 1
Apples
Apples
Apples
Apples
File 2
Bananas
Bananas
Bananas
Bananas (4 Replies)
i have variables RECIPIENTS_DEVL,RECIPIENTS_UACC,RECIPIENTS_PROD
i have a case statement to get the phase variable:
case ${WMD_UPHASE1} in
u) WMD_UPHASE4=UACC;;
i) WMD_UPHASE4=DEVL;;
p) WMD_UPHASE4=PROD;;
d) WMD_UPHASE4=DEVL;;
*) WMD_UPHASE4=DEVL;;
esac
I am unable to... (3 Replies)
I am trying to read a input file which has two columns separated by space
Input file
server1 server2
server3 server4
server5 server6
When i execute the below while code it reads line by line and a and b variables are able to successfully fetch the values
while read a b
do
echo "$a"
echo... (5 Replies)
Discussion started by: chidori
5 Replies
LEARN ABOUT XFREE86
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)