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Full Discussion: Variable syntax error in $?
Top Forums Shell Programming and Scripting Variable syntax error in $? Post 302812609 by Rahul619 on Sunday 26th of May 2013 12:31:40 PM
Old 05-26-2013
Variable syntax error

Code:
Code:
#!/bin/csh -f

################
# Set Variables
################

set curdate = `date '+%Y%m%d'`
set datetime = `date '+%m%d%y_%H%M'`

grep abc abc.txt

echo $?

exit(0)

Ideally this should return status 2 since there is no file called as abc.txt in my directory.. but it throws a variable syntax error

---------- Post updated at 11:31 AM ---------- Previous update was at 11:28 AM ----------

my actual need is I should have a script which should call a script 1.sc and when it is success it should call 2.sc and when then so on .. the 2nd script should not run unless 1.sh is completed.
I tried using ps -ef | grep scriptname | awk '{print $2}' , but it always returns some PID . so i tried using echo $? .. please corrct me if my logic is wrong ..

Last edited by Franklin52; 05-27-2013 at 03:09 AM.. Reason: Code tags
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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