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Top Forums UNIX for Dummies Questions & Answers Searching a pattern and picking rows underneath them! Post 302811805 by Scott on Friday 24th of May 2013 08:52:55 AM
Old 05-24-2013
What have you tried?
 

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IFX_FETCH_ROW(3)							 1							  IFX_FETCH_ROW(3)

ifx_fetch_row - Get row as an associative array

SYNOPSIS
array ifx_fetch_row (resource $result_id, [mixed $position]) DESCRIPTION
Fetches one row of data from the result associated with the specified result identifier. Subsequent calls to ifx_fetch_row(3) would return the next row in the result set, or FALSE if there are no more rows. PARAMETERS
o $result_id -$result_id is a valid resultid returned by ifx_query(3) or ifx_prepare(3) (select type queries only!). o $position - An optional parameter for a "fetch" operation on "scroll" cursors: NEXT, PREVIOUS, CURRENT, FIRST, LAST or a number. If you specify a number, an "absolute" row fetch is executed. This parameter is optional, and only valid for SCROLL cursors. RETURN VALUES
Returns an associative array that corresponds to the fetched row, or FALSE if there are no more rows. Blob columns are returned as integer blob id values for use in ifx_get_blob(3) unless you have used ifx_textasvarchar(1) or ifx_byteasvar- char(1), in which case blobs are returned as string values. EXAMPLES
Example #1 Informix fetch rows <?php $rid = ifx_prepare ("select * from emp where name like " . $name, $connid, IFX_SCROLL); if (! $rid) { /* ... error ... */ } $rowcount = ifx_affected_rows($rid); if ($rowcount > 1000) { printf ("Too many rows in result set (%d) <br />", $rowcount); die ("Please restrict your query<br /> "); } if (! ifx_do ($rid)) { /* ... error ... */ } $row = ifx_fetch_row ($rid, "NEXT"); while (is_array($row)) { for (reset($row); $fieldname=key($row); next($row)) { $fieldvalue = $row[$fieldname]; printf ("%s = %s,", $fieldname, $fieldvalue); } printf(" <br />"); $row = ifx_fetch_row($rid, "NEXT"); } ifx_free_result ($rid); ?> PHP Documentation Group IFX_FETCH_ROW(3)
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