Global replace with perl in bash Post: 302806705

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Global search ok...but replace?

Gurus, I have in my /tmp directory 26 files "filea", "fileb"..."filez". Each file contains the name of a database 'dwora' at many, many places within each file. My boss decided to change the name of the db so I need to do (what i'd call) a global search&replace of that string in all my...

2. Shell Programming and Scripting

global replace...

Hi, I have a dir containing many shell scripts. Each of these shell scripts state a database name (always the same), which I need to change to be a new database. grep <database name> * brings back all the lines containing the database name. However, I need to change them to be something...

3. Shell Programming and Scripting

Perl: Global Search and replace

I have a file where the rows correspond to individuals and the columns are about 106 variables. Each variable is coded as either ACGT, and "missing" is coded as blank. This is a tab delimited file. I'm trying to replace all blanks (" ") with 0. The simple script I have is only replacing some of the...

4. Shell Programming and Scripting

Global replace with sed

Hi, I need to change some strings from A to B in a number of files within a directory. Please can someone advise how do I do that? Many thanks

5. Shell Programming and Scripting

Global search and replace across multiple files

Hi all I'm in need of a command which can replace a specified string with another string - across multiple files within multiple sub-directories (I intend to run it from / ) I've used the following to get a list of the files: find . | xargs grep <string1> But that's as far as I've got....

6. Shell Programming and Scripting

Global replace in vi with no escape required

Hi all, I want to replace a string of words but i dont want to worry about escaping the characters in that string . For e.g. If my string is "work/" and i want to replace it with "nowork" .I have to type %s/work\//nowork/g Is there a way by which I wont need to worry about the data in...

7. UNIX for Dummies Questions & Answers

Vi global replace command

I am wondering what way, I can remove a certain text with nothing. for example: MyVariable=Y7UHNI to only: Y7UHNI removing 'MyVariable=' globally? thanks

8. Shell Programming and Scripting

Global exit listener in bash

I have a script with a whole lot of different functions and want to set teh script so that at any point a key or series of keys can be pressed to exit out and into the main menu function. Rather this than endlessly creating, 'Return to main' menus. Something along the lines of Ctrl+q for example...

9. Programming

Global variable in for loop (BASH)

Hello, I'm trying to read the variable "pause" from a for loop without luck. The function is dependant on the outcome of the test within the loop. If i run this, pause is always 0 within the function. Any ideas? Thanks. pause=0 users=1 (for (( ; ; )) do speed=`cat speed.log` ...

10. UNIX for Dummies Questions & Answers

Global replace command help

Hello - I am trying to use a global replace command but its not working. Here is the cmd I am using in vi: :%s/OLD/NEW/g However, in my "NEW" I already have a "/" which is not making the replace work: :%s/mytestscript.com:33232/mytestscript:70245/test.com/g the...

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)