awk question Post: 302805285

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I have the following error: ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }' Syntax Error The source line is 1. The error context is BEGIN >>> NR <<< > 1 { print $2, $9 } awk: 0602-500 Quitting The source line is 1. What I want to do is ls a directory, skip the first...

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I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text. Can anyone provide some assistance. Thanks!!

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How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06 4.35109e+06 4.36134e+06 4.4535e+06 5.47752e+06 5.48777e+06 7.52554e+06 7.73036e+06 9.06158e+06 :confused: thank you

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Hi, in the following script, what does " a=$0} END " mean ? do we need that ? Thanks awk '{a=$0} END {for (i=NR; i>=1; i--) print a}' file

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Can anyone help with this this one liner: nawk -v RS='' '$1=$1' InputFile What I have in the file: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958 -0.0005763523138347 0.0 And the output I want: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958...

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Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello...

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awk question.

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: im using ls -l | xargs | awk '{what ever files here}' im trying to get something that looks like this...

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awk question : system output to awk variable.

Hi Experts, I am trying to get system output to capture inside awk , but not working: Please advise if this is possible : I am trying something like this but not working, the output is coming wrong: echo "" | awk '{d=system ("date") ; print "Current date is:" , d }' Thanks,

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ppi::token::regexp::match5.18

PPI::Token::Regexp::Match(3)				User Contributed Perl Documentation			      PPI::Token::Regexp::Match(3)

NAME

       PPI::Token::Regexp::Match - A standard pattern match regex

INHERITANCE

	 PPI::Token::Regexp::Match
	 isa PPI::Token::Regexp
	     isa PPI::Token
		 isa PPI::Element

SYNOPSIS

	 $text =~ m/match regexp/;
	 $text =~ /match regexp/;

DESCRIPTION

       A "PPI::Token::Regexp::Match" object represents a single match regular expression. Just to be doubly clear, here are things that are and
       aren't considered a match regexp.

	 # Is a match regexp
	 /This is a match regexp/;
	 m/Old McDonald had a farm/eieio;

	 # These are NOT match regexp
	 qr/This is a regexp quote-like operator/;
	 s/This is a/replace regexp/;

METHODS

       There are no methods available for "PPI::Token::Regexp::Match" beyond those provided by the parent PPI::Token::Regexp, PPI::Token and
       PPI::Element classes.

       Got any ideas for methods? Submit a report to rt.cpan.org!

SUPPORT

       See the support section in the main module.

AUTHOR

       Adam Kennedy <adamk@cpan.org>

COPYRIGHT

       Copyright 2001 - 2011 Adam Kennedy.

       This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.

       The full text of the license can be found in the LICENSE file included with this module.

perl v5.18.2							    2011-02-25					      PPI::Token::Regexp::Match(3)

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LEARN ABOUT MOJAVE

ppi::token::regexp::match5.18