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Full Discussion: C++/ROOT Memory Allocation?
Top Forums Programming C++/ROOT Memory Allocation? Post 302802807 by hanson44 on Sunday 5th of May 2013 12:37:08 AM
Old 05-05-2013
Quote:
I notice that when I just loop through 10,000
times my free memory loses ~0.5 gigabytes.
What do you mean by "loop through" here? Do you mean you invoke the program from the command line 10,000 times? Or is there another function that calls MontyHall2 () function 10,000 times. Or do you mean that iterations is 10,000?

What is 389? Ever heard of a "magic number"? Smilie
 

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USLEEP(3)						   BSD Library Functions Manual 						 USLEEP(3)

NAME
usleep -- suspend execution for interval of microseconds LIBRARY
Standard C Library (libc, -lc) SYNOPSIS
#include <unistd.h> int usleep(useconds_t microseconds); DESCRIPTION
The usleep() function suspends execution of the calling process until either the number of microseconds specified by microseconds have elapsed or a signal is delivered to the calling process and its action is to invoke a signal catching function or to terminate the process. The suspension time may be longer than requested due to the scheduling of other activity by the system. The microseconds argument must be less than 1,000,000. If the value of microseconds is 0, then the call has no effect. RETURN VALUES
On successful completion, usleep() returns 0. Otherwise, it returns -1 and sets errno to indicate the error. ERRORS
The usleep() function may fail if: [EINVAL] The microseconds interval specified 1,000,000 or more microseconds. SEE ALSO
nanosleep(2), sleep(3) STANDARDS
The usleep() function conforms to X/Open Portability Guide Issue 4, Version 2 (``XPG4.2''). It later appeared in the POSIX standard, but in IEEE Std 1003.1-2004 (``POSIX.1'') it was marked as legacy and the use of nanosleep(2) was recommended instead. The IEEE Std 1003.1-2008 (``POSIX.1'') revision removed usleep() from the specification. HISTORY
The usleep() function appeared in 4.3BSD. BSD
April 29, 2010 BSD
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