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Top Forums UNIX for Dummies Questions & Answers Any awk one liner to print df output? Post 302802001 by hanson44 on Thursday 2nd of May 2013 06:42:50 PM
Old 05-02-2013
Quote:
is any way to print the lines matching where the capacity is >= 80%?
Code:
$ grep "\([89][0-9]\)%\|100%" input
server01:/vol/vol_02/02 284164096 255495160 28668936    90%    /nas_mnt/server01/vol_02/02
server01:/vol/vol_03/03 8388608 7686776  701832    92%    /nas_mnt/server01/vol_03/03
server01:/vol/vol_06/06 3145728 2591832  553896    83%    /nas_mnt/server01/vol_06/06
server01:/vol/vol_07/07 6266880 5037936 1228944    81%    /nas_mnt/server01/vol_07/07

 

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LORDER(1)						      General Commands Manual							 LORDER(1)

NAME
lorder - find ordering relation for an object library SYNOPSIS
lorder file ... DESCRIPTION
The input is one or more object or library archive (see ar(1)) files. The standard output is a list of pairs of object file names, meaning that the first file of the pair refers to external identifiers defined in the second. The output may be processed by tsort(1) to find an ordering of a library suitable for one-pass access by ld(1). This brash one-liner intends to build a new library from existing `.o' files. ar cr library `lorder *.o | tsort` FILES
*symref, *symdef nm(1), sed(1), sort(1), join(1) SEE ALSO
tsort(1), ld(1), ar(1) BUGS
The names of object files, in and out of libraries, must end with `.o'; nonsense results otherwise. LORDER(1)
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