Hi folks,
I am wondering how to output awk back to a variable.
I am new to Unix/Linux.
I am trying to get rid of a decimal number and put the output back in a variable for further use in the script. here is how I used awk:
var=$1
echo $var |awk '{print $1 *100}' | $var
echo $var
this... (4 Replies)
I wanna use a system function to deal with several data. So I use awk variable FILENAME to transfer the file directory to system command, but it does not work.
I use a shell function "out_function" to deal with data and save the result in another directory with the same file name.
How can I... (2 Replies)
Hi
I am trying to store the output of awk into a variable in a shell script. I can run it successfully from the command line but not from a ksh shell script.
ls -al test.txt | grep -v grep | awk '{print $1}'
returns -rw-r--r--
#!/bin/ksh
perm=$(`ls -al test.txt | grep -v grep | awk... (2 Replies)
Not sure why it is not working the following :
set -- $@
stype ="a"
for shell_args in "$@"
do
$stype=` awk '{print substr ("'"$shell_args"'", 0, 3)}' `
echo $stype
done
Thank you (5 Replies)
hello,
I want to print my output into a file inside of awk, but I don't know it could wokr with using system (piping the $1-4 to another shellskript):
cat file.txt |awk '{ if ($5==2) {dataname=$1 "_" $2 "_" $3 "_" $4 "_typing.rad"
befehl=".gen_test " $7 " " $8 " " $8
system(befehl) >... (5 Replies)
Hi everybody,
I am working on a bigger awk script in which one part is comparing the size of two files.
I want to evaluate which file is bigger and then just save the bigger one.
I got it all working except for the part where I want to figure out which file is bigger; the one awk is currently... (2 Replies)
Hi all,
Hope someone can help me out here.
I have this BASH script (see below)
My problem lies with the variable path.
The output of the command find will give me several fields. The 9th field is the path. I want to captured that and the I want to filter this to a specific level.
The... (6 Replies)
hi i want to find the size of a folder and assign it to a variable and then compare if it is greater than 1 gb.
i am doin this script, but it is throwing error....
#!/bin/ksh
cd . | du -s | size = awk '{print $1}'
if size >= 112000
then
echo size high
fi
ERROR : (4 Replies)
I am reasonably capable with awk and its quirks, but not with shell weirdness. This has to be Bourne Shell for portability reasons. I have an awk program that is working just fine; it handles multiple input streams and produces several reports, based on the request (-v Variables). In addition... (3 Replies)
Hi,
I am trying to use variable output in awk to append a string to a word in a line. But that is not happening. Could you please help me on this.
YouTube Video Tutorial: How to Use Code Tags and Format Posts @UNIX.com
The below is the code
#!/bin/ksh
set -x
src=/users/oracle/Temp... (2 Replies)
Discussion started by: pvmanikandan
2 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)