i am a new user of C-shell script.
I want to know can i create a substring in a string.
That means when i got a variable $input = "it is number 2"
I want to get the "2" to be another variable.
Can i do that in C-shell and how to ?
Thank you so much
dinodash (0 Replies)
Hi All,
Following is the output of a find commnd to locate log directories for various projects of UNIX AIX box:
/home/hbinz6pf/projectlibs/dpr_pfsdw_dev/&PH&
/opt/tools/ds/Template/&PH&
/data/ds/ms/hmsdw/projectlibs/dpr_ms_dev/&PH&
/data/ds/riskmi/projectlibs/dpr_riskmi_dev/&PH&... (5 Replies)
Hi
I am writing a script file which sends the log files along with their size in a folder named log to a file called temp.log using the following cmd:
ls -st 190_GSTV_HUX_003QISCGSK026** >> /home/user/temp.log
the temp.log looks like this:
16 190_GSTV_HUX_003QISCGSK026_message070321.log
... (11 Replies)
Hi
I'm new to Shell scripting. Someone please help me in extracting a portion of string from a file.
Eg:
I got a file like, Readme.txt and has the following name value pairs
input1 : /homes/input1/
input2 : /homes/input2/
...
...
When I give the parameter input1, the value... (3 Replies)
I need a help in getting substring of each line in input file.
I am writing a script that will read a file from a directory on daily basis, I mean everyday a new file will be stored in this directory, it will replace old file. I have to read contents of this file, the contents will be as... (5 Replies)
This is the data I am having in a file
Just for sample I have given 3 records. The file which I am having consists of n number of records.
ABC123 10 01/02/2008 2008-01-03-00.00.00.000000
DYUU 22 02/03/2008 2008-01-04-00.00.00.000000
RF33 88 03/05/2008 2008-01-05-00.00.00.000000
... (24 Replies)
:)
Hi,
I want to script for this scenerio,
OSR Settings
Scenario : We are looking to find all the *.a files from the following locations in the filesystem of a server.
OSR Directories
/etc
/bin
/usr/bin
/usr/sbin
/var/adm
These *.a files should have the permissions on... (12 Replies)
I want to make a script that check for the argument passed to it and generates an error in case any character/string argument passed to it.
I am using below code, but its not working. can anyone help.
#!/bin/bash
if ]; then
echo 'An integer argument is passed to the script hence... (3 Replies)
Hi Masters,
I need to remove lines when date format is below certain date
My file input
20140906|ALASKA|USASEL|TARPUNG|2014-03-01|82176614040|20|1
20140906|ALASKA|USATENG|CRUIEX|2014-08-01|81267079997|5|0
20140906|ALASKA|USASEL|CRUIEMBANG|2013-10-01|82280779814|9|0... (4 Replies)
Hi all,
Please, i'd like to extract string just before '.fr'.
Here is some lines of my file:
g-82.text.text1.fr.worker1
g-xx.yyyyyy.zzzz.fr.worker2
i'd like to extract this text:
g-82.text.text1
g-xx.yyyyyy.zzzz
Please, which command i have to use in my script shell ?
... (16 Replies)
Discussion started by: chercheur111
16 Replies
LEARN ABOUT PHP
datefmt_set_lenient
DATEFMT_SET_LENIENT(3) 1 DATEFMT_SET_LENIENT(3)IntlDateFormatter::setLenient - Set the leniency of the parser
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient)
DESCRIPTION
Procedural style
bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient)
Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows
the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized
tokens, or invalid values ("February 30th") are not accepted.
PARAMETERS
o $fmt
- The formatter resource
o $lenient
- Sets whether the parser is lenient or not, default is TRUE (lenient).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
datefmt_set_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt, false);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : ".intl_get_error_message();
echo "
Error_code is : ".intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : 66038400
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_is_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_LENIENT(3)