Hi frnds...
I m facing very irritating problem already waisted my 2 days..
I have a following script..( i am pasting only the main code)
ftp -ivn 213.194.40.77 <<FTP
user $user $password
binary
cd $FileDir/out
lcd $localpath
get $file
rename $FileDir/out/$file $FileDir/tmp/$file... (1 Reply)
Within my script, there is this following if, then statement. It basically looks for files in a directory that match a certain naming convention (bingofile*.DAT) and are non empty files and moves these files to a diff. directory. The script works okay if there is only one file matching the search... (4 Replies)
hi
i'm trying to do program that counts the total no of words from files from a directory and all it's subdirectories.ang i get the binary operator expected error at line 7 and line 12.can you please help me with this as quick as possible?
if test -d $1
then
sum=0
for name in $1/*
do... (2 Replies)
Hello,
I am not sure, where I am missing in the scirpt, I am trying to grep few users from /etc/passwd file and if exists, I added line to echo as user exist, if not create it.
#!/bin/bash
for vid in v707 z307 z496 z163 z292 ; do
if
then
echo " $vid User exists "
else
... (2 Replies)
Hello Unix forum.
I'm encountering the following error "binary operator expected error" and I cannot seem to solve the issue.
I have the following source files to process:
CPA_LOOKUP_dat.lst
PROFILE_TXN__dat.lst
TRANSACTION_CODE_dat.lst
PROFILE_TXN_OUT_OF_BALANCE_dat.lst ... (2 Replies)
Hi,
I have a shell script which fetches the MRP status and the LAG status.
When I execute it manually like, sh <script_name>, it fetches the output as expected, but when I schedule through crontab, it's not working as expected.
Any help would be really appreciated.
Here is the code... (3 Replies)
Hi Team,
I just started to learn shell scripting and i got this script from an online book and tried to run in my terminal. But it throws error message.
echo $0
-bash
echo $UID
501
cat check_rootuser.sh
#!/bin/bash
# Run as root, of course.
LOG_DIR=/var/log
ROOT_UID=0 # Only users... (4 Replies)
Hi,
Below is my code where i m trying to grep for name>$servername in manages*.tmp files
servername="serv1"
set manages*.tmp
if ; then
However, i get the below error at the if condition:
Can you please suggest how can i fix the problem. (3 Replies)
Discussion started by: mohtashims
3 Replies
LEARN ABOUT FREEBSD
atf-sh
ATF-SH(1) BSD General Commands Manual ATF-SH(1)NAME
atf-sh [-s shell] -- interpreter for shell-based test programs
SYNOPSIS
atf-sh script
DESCRIPTION
atf-sh is an interpreter that runs the test program given in script after loading the atf-sh(3) library.
atf-sh is not a real interpreter though: it is just a wrapper around the system-wide shell defined by ATF_SHELL. atf-sh executes the inter-
preter, loads the atf-sh(3) library and then runs the script. You must consider atf-sh to be a POSIX shell by default and thus should not
use any non-standard extensions.
The following options are available:
-s shell Specifies the shell to use instead of the value provided by ATF_SHELL.
ENVIRONMENT
ATF_LIBEXECDIR Overrides the builtin directory where atf-sh is located. Should not be overridden other than for testing purposes.
ATF_PKGDATADIR Overrides the builtin directory where libatf-sh.subr is located. Should not be overridden other than for testing purposes.
ATF_SHELL Path to the system shell to be used in the generated scripts. Scripts must not rely on this variable being set to select a
specific interpreter.
EXAMPLES
Scripts using atf-sh(3) should start with:
#! /usr/bin/env atf-sh
Alternatively, if you want to explicitly choose a shell interpreter, you cannot rely on env(1) to find atf-sh. Instead, you have to hardcode
the path to atf-sh in the script and then use the -s option afterwards as a single parameter:
#! /path/to/bin/atf-sh -s/bin/bash
ENVIRONMENT
ATF_SHELL Path to the system shell to be used in the generated scripts.
SEE ALSO atf-sh(3)BSD September 27, 2014 BSD