Hello
I need some help with this job.
file.txt
----- cut ----
TARGET
13/11/08
20:43:21
POINT 1
MOVE 8
772102y64312417771
TARGET
13/11/08
21:10:01
POINT 2
MOVE 5
731623jjd12njhd
----- cut ----
this is the example.
i need to grep for the word TARGET and print next 4 lines like... (1 Reply)
Hello
I have a silly question. I need to grep a match in text file
and then print 5 lines after it.
grep -A 5 .... do it.
OK
The next thing I can not handle is I need each output to be on 1 line
match line2 line3 line4 line5
match line2 line3 line4 line5
etc..
I will really... (10 Replies)
Hi,
Anyone help me to print the lines from the flat file between 879th line number and 1424th line number.
The 879 and 1424 should be passed as input to the shell script(It should be dynamic).
Can any one give me using sed or awk?
I tried using read, and print the lines..Its taking too... (3 Replies)
Hi all,
on Solaris 10, I'd like to print a range of lines starting at pattern but also including the very first line before pattern.
the following doesn't print the range starting at pattern and going down to the end of file: cat <my file> | sed -n -e '/<pattern>{x;p;}/'
I need to include the... (1 Reply)
Hi,
I have a file as below
This is the line one
This is the line two
<\XMLTAG>
This is the line three
This is the line four
<\XMLTAG>
Output of the SED command need to be as below.
This is the line one
This is the line two
<\XMLTAG>
Please do the need to needful to... (4 Replies)
Data:
Pattern Data Data Data
Data Data Data
Data Data Data
...
With awk, how do I print the pattern matching line, then the subsequent lines following the pattern matching line. Varying number of lines following the pattern matching line. (9 Replies)
Hi,
I have a simple problem but i guess stupid enough to figure it out. i have thousands rows of data. and i need to find match patterns of two columns and print the number of rows. for example:
inputfile
abd abp 123
abc abc 325
ndc ndc 451
mjk lkj... (3 Replies)
I need to fetch particular string from log file based on grep condition match.
Actual requirement is need to print the next word from the same line based on grep string condtion match.
File :Java.lanag.xyz......File copied completed : abc.txt
Ouput :abc.txt
I have used below... (5 Replies)
Hi ,
My record file , need to print up to above (DATA array)(there may be n no lines ) , grep "myvalue" row now .....suggest me some options
--- DATA Array---
record type xxxxx
sequence type yyyyy
2
3---> data1
/dev/
--- DEVICE ---
MAXIMUM_People=
data_blocks=
MY_value=2
xyz
abc ... (0 Replies)
Hi,
I have attached an output file which is some kind of database file mapping. It is basically like an allocation mapping of a tablespace and its datafile/s.
The output is generated by the SQL script that I found from 401 Authorization Required
Excerpts of the file are as below:
... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT OSX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD