awk to find the max Post: 302791163

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Hi, i have a file with numbers in it and i was wondering if there's a script i could use to find the max number and have that printed to a new file? example a.txt 18 26 47 34 27 so find the max number in a.txt and print it to b.txt. Thanks!

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Is there a simple way of calculating the max number in a set of variables, so a=1 b=3 c=6 d=30 something that says e=max($a, $b, $c, $d) I've found a way to do it using: a="1" b="3" c="5" d="50" if ; then t=$a else

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FILE_NAME VER TYPE DELETED_DATE CREATED_DATE SIZE LOCATION hello 1 d 2010-08-09 2010-08-09 4096 /home/xxxxx/project/ hello 2 d 2010-08-09 2010-08-09 4096 /home/xxxxx/project/ hello 3 d 2010-08-09 2010-08-09 4096 /home/xxxxx/project/ hello 4 d 2010-08-09 2010-08-09 4096 /home/xxxxx/project/ ...

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to find min and max value for each column!

Hello Experts, I have got a txt files which has multiple columns, I want to get the max, min and diff (max-min) for each column in the same txt file. Example: cat file.txt a 1 4 b 2 5 c 3 6 I want ouput like: cat file.txt a 1 4 b 2 5 c 3 6 Max 3 6 Min 1 4 Diff 2 2 awk 'min=="" ||...

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I have a file about cpu load like this (the first column is time, the second column is cpu load): 11:34:01 0.10 11:34:37 0.05 11:35:13 0.03 11:35:59 0.06 11:38:00 0.02 11:38:09 0.17 11:39:48 0.06 I need to find the max value of the second column so I write the script as follows max=0...

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Using awk to find max and printing entire line

Hi folks, I am very new to awk. I have what is probably a very simple question. I'm trying to get the max value of column 1, but also print column 2. My data looks like this: 0.044|2000-02-03 14:00:00 5.23|2000-02-03 05:45:00 5.26|2000-02-03 11:15:00 0|2000-02-01 18:30:00 So in this case...

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awk script to find min and max value

I need to find the max/min of columns 1 and 2 of a 2 column file what contains the special character ">". I know that this will find the max value of column 1. awk 'BEGIN {max = 0} {if ($1>max) max=$1} END {print max}' input.file But what if I needed to ignore special characters in the...

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Find Max value of line and print

I need to find the max value of all columns except the 1st column and print the answer along with the 1st column. Input 123xyz 0 0 1 2 0 0 0 0 0 0 0 234xyz 0 0 0 0 0 0 0 0 0 0 0 345xyz 0 0 1 0 0 0 ...

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)