i read the variable ph from file and i wanna to print it in awk.
example
ph=`cat tmpbatch`
tail h.txt|grep "| |"|awk -F"|" '{ print "@unpdx.sql",$5 }'"$ph"
i try this but it does not work (8 Replies)
i want to print the column file using awk or cut in dynamic manner
like
trmp=2;temp1=1;temp3=2
awk 'BEGIN{OFS=IFS="\t"} {print $temp,$temp1,$temp3}' client_data.txt
or cut -f $temp1,$temp2,$temp3 -d"\t" file_name .
but it is showing error , In awk can i use variable as in printing... (36 Replies)
hi,
i have store variable in $var i want to print it in $3 of file using awk.
how can i do it?
file :
var1,var2,var3
var5,var6,var7
var8,var9,var10
.
.
.
i want to print $var in $3 ( for example var3 or var7 or var10)
thanks (3 Replies)
:b:Hi All,
I have a part of a script below:
var1="value1"
awk 'BEGIN {printf("%36s \n ","value1")}'
Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement.
Is this possible?
If so, what is the modified awk command?
Thanks in advance
JS (1 Reply)
I have list of files:
ls
a.pdf
b.pdf
c.pdf
and so on...
and I have a file like this:
cat file1
apple
mango
pear
and so on...
I want to rename my file like this: (7 Replies)
hey,
just want to ask how to do this.
ex.
g="hi i am john"
h=`echo $g | awk '{print $2}'`
echo $h
OUTPUT is 'i'
What if I want to use a variable instead of using '2', how do I do that?
Because this one does not work:
a=2
h=`echo $g | awk '{print ${$a}}'`
this one also does not... (3 Replies)
Hi,
I am trying to do this:-
FILE=application.log
PID=12345
FILE=`echo $FILE | awk -F "." '{print $1 "$PID" $2}'`
echo $FILE
application$PIDlog
I need the output to be application12345.log but I am not sure how to get the $PID variable into the output. I have tried various things... (3 Replies)
Hy!
I need to post-process some data files which have variable (and periodic) number of fields. For example, I need to square (data -> data*data) the folowing data file: -5.34281E-28 -3.69822E-29 8.19128E-29 9.55444E-29 8.16494E-29 6.23125E-29
4.42106E-29 2.94592E-29 1.84841E-29 ... (5 Replies)
Dear Unix Gurus,
input:
A|1|2|3|4|5
B|1|2|3|4|3
C|1|2|3|4|1
D|1|9|3|4|12
output:
A_(5);B(3);C(1)|1|2|3|4
D_(12)|1|9|3|4
Details:
If $2, $3, $3, $5 are identical, concatenate $1 and associated $NF together in the first field.
But I am trying to do the above by passing the identical... (6 Replies)
Discussion started by: beca123456
6 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)