I have a variable which consists of a string like this:
001 aaabc 44 a bbb12
How do I extract each substring, delimited by the spaces, into new variables - one for each substring?
eg var1 will be 001, var2 will be aaabc, var3 will be 44, var4 will be a, etc?
I've come up with this:... (2 Replies)
Dear all,
i dont know how to split one variable value in 2 variable. please send me any example.
variable1= "abcde developer"
now i want to seperate the values and seperator is space. (6 Replies)
Somehow I can't get it for this basic bash problem. maybe someone can help.
What I try to do is:
a="world"
b="hello"
how can I move this into $c so that I can replace "helloworld" with "world hello" in sed like:
sed "s/\helloworld/ ${c}...
I tried several combinations but all with... (4 Replies)
Hello,
I have a paramter $param consisting just of two literals and want to split it into two parameters, so I can combine it to a new parameter <char1><string><char2>, but the following code didn't work:
tmp_PARAM_1=cut -c1 $PARAM
tmp_PARAM_2=cut -c2 $PARAM... (2 Replies)
Hello, I am a new joiner to the forum, and have what i hope is a simple question, however I can't seem to find the answer so maybe it is not available within bash scripting.
I intend to use the below script to archive files from multiple directories at once by using a loop, and a variable (n)... (10 Replies)
Hello,
Here is my problem using KSH
I have a set of compound variables, let say cmp_var1 cmp_var2
The names of these variables are stored in an indexed array.
How can I access the subfields of these compound variables ?
I tried:
set -A cmp_varnames=(cmp_var1 cmp_var2)
for cmp in... (4 Replies)
Experts,
I want to set value of variables like this in bash shell:
i=5 ; L=100
I want variable d5 (that is d(i) ) to be assign the value of $L ,
d$i=$L ; echo $d5
Not working
Thanks., (3 Replies)
Hi,
I am having a bit of trouble with the below code:
file=/path/to/file
for i in 03 06 07 21; do
if ; then
eval count$i=`grep -c word $file-$i`
fi
done
Totalcount=0
for i in 03 06 07 21; do
if ; then
echo $count$i variable not exist;
else Tcount=`expr $Tcount + $count$i`;
fi... (3 Replies)
Hi Guys,
I was scratching my head for this for half a day... finally not successful :confused:
Following is the problem
I have a variable
$ var1=123
$ var2-234
$ var3=345
and another Variable
$ i=1
Now i wanted to save these into a Variable as shown below
for i in 1 2 3
do... (5 Replies)
Dear Forum members,
I am having trouble getting the complete filename (and directory path) in a variable.
Output directory mentioned in the code have three files:
DISPLAY_CITY_DETAILS_15-05-2019-08-29-26_MIGRATE_london.out
DISPLAY_CITY_DETAILS_15-05-2019-08-29-26_MIGRATE_paris.out... (4 Replies)
Discussion started by: chetanojha
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)