The short answer is: you can't The single char "ls" shows is the End-of-File-character (literally a "^D") and it isn't possible with "vi" to delete it. In fact "vi" will even append such a EOF char to a file if it was missing.
Generate a file with "touch", it will have 0 characters. Now open this in "vi", write some text, delete it completely (this way "vi" thinks you have changed the file, do NOT use the undo-function) and save the file. You will notice that it has also 1 character in it - the EOF char.
I hope this helps.
bakunin
Sorry, but no. UNIX text files do not have an End-of-File character. Each line in a text file is terminated by a <newline> character. If you have a file open in vi and issue the commands:
(which deletes all lines in the file), the size of file will be 0 bytes.
If you have exactly one line in a file and you edit it with vi and delete all of the characters on the line by repeatedly executing the x command until the line is empty and then issue the command: :w file
then the size of file will be 1 byte because you didn't delete the line, you just deleted the characters on the line preceding the terminating <newline> character.
The current line (including the terminating <newline> character can also be deleted in vi with the dd command.
These 2 Users Gave Thanks to Don Cragun For This Post:
Dear Members,
We have a file which contains some special characters. I need to replace these special character by a new line character(\n).
The Special character is \x85.
I am not sure what this character means and how we can remove it.
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Hi All,
i am trying to remove all special charecters().,/\~!@#%^$*&^_- and others from a tab delimited file.
I am using the following code.
while read LINE
do
echo $LINE | tr -d '=;:`"<>,./?!@#$%^&(){}'|tr -d "-"|tr -d "'" | tr -d "_"
done < trial.txt > output.txt
Problem
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Hi Guys,
My requirement is to remove any invisible and special characters from the file like control M(carriage return) and alt numerics and it should not replace @#!$%
abc|xyz|acd¥£ó
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Rakesh (1 Reply)
Hi Guys,
My requirement is to remove any invisible and special characters from the file like control M(carriage return) and alt numerics and it should not replace @#!$%
abc|xyz|acd¥£ó
adc|123| 12áí
Please help on this.
Thanks
Rakesh (1 Reply)
Discussion started by: rakeshp
1 Replies
LEARN ABOUT CENTOS
uuencode
UUENCODE(5) File Formats Manual UUENCODE(5)NAME
uuencode - format of an encoded uuencode file
DESCRIPTION
Files output by uuencode(1) consist of a header line, followed by a number of body lines, and a trailer line. The uudecode(1) command will
ignore any lines preceding the header or following the trailer. Lines preceding a header must not, of course, look like a header.
The header line is distinguished by having the first 6 characters begin This is followed by a mode (in octal), and a string which names
the remote file. A space character separates the three items in the header line.
The body consists of a number of lines, each at most 62 characters long (including the trailing newline). These consist of a character
count, followed by encoded characters, followed by a newline. The character count is a single printing character, and represents an inte-
ger, the number of bytes the rest of the line represents. Such integers are always in the range from 0 to 63 and can be determined by sub-
tracting the character space (octal 40) from the character.
Groups of 3 bytes are stored in 4 characters, 6 bits per character. All are offset by a space to make the characters printing. The last
line may be shorter than the normal 45 bytes. If the size is not a multiple of 3, this fact can be determined by the value of the count on
the last line. Extra garbage will be included to make the character count a multiple of 4. The body is terminated by a line with a count
of zero. This line consists of one ASCII space.
The trailer line consists of end on a line by itself.
SEE ALSO uuencode(1), uudecode(1), uusend(1), uucp(1), mail(1)HISTORY
The uuencode file format appeared in BSD 4.0 .
UUENCODE(5)